To create the new figure, we must multiply each coordinate by the scale factor, which is 1/2 in this case.
So j(-2,2) becomes j'(-1,1)
K(4,2) becomes K'(2,1)
L(4,-2) becomes L'(2,-1)
and M (-2,-2) becomes M'(-1,-1)
The scale factor is between 1 and 0 which means that this dilation is a reduction that will shrink the original figure to a smaller one.
First, find m, the slope of the line.
(1-3)/(5-1) =
-2/4 =
-1/2
Next, choose either point to write the point slope form. I will show the outcome of both points.
1. Using point (1, 3)
y-y1=m(x-x1)
y-3=(-1/2)(x-1)
————————
y-3=-1/2x+1/2
y=-1/2x+7/2
2. Using point (5,1)
y-y1=m(x-x1)
y-1=-1/2(x-5)
————————
y-1=-1/2x+5/2
y=-1/2x+7/2
The outcome is the same.
Answer:
Left: The substance is decreasing by 1/2 every 12 years
Right: The substance is decreasing by 5.61% each year
Step-by-step explanation:
exponential decay
A = P(1-r)ᵇⁿ, where A is the final amount, P is the initial amount, r is the rate decreased each time period, b is the number of years, and n is the number of times compounded each year
let's write each formula in terms of this
left:
f(t) = 600(1/2)^(t/12)
matching values up...
A = P(1-r)ᵇⁿ
A = f(t)
P = 600
1 - r = 1/2 -> r = 1/2
t/12 = bn -> b = number of years = t, so bn = b/12 -> n = 1/12. Thus, it is compounded 1/12 times each year, so it is compounded every t*12 = 12 years. If it was compounded each month, it would be compounded 12 times a year
Thus, this is decreasing by a rate of 1/2 each 12 years
right:
f(t) = 600(1-0.0561)^(t)
matching values up...
A = P(1-r)ᵇⁿ
A = f(t)
P = 600
1 - r = 1 - 0.0561 -> r = 0.0561 = 5.61%
t = bn -> b = number of years = t, so bn = b -> n = 1. Thus, it is compounded annually (1 time each year)
Thus, this is decreasing by a rate of 5.61% each year
Answer:42
Step-by-step explanation:
Because 7 times 3 is 21 so then you'll times 7 by the other 3 and 21+21=42
