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Tema [17]
3 years ago
7

2(5x+4)-3xOnly for Best users.​

Mathematics
2 answers:
OlgaM077 [116]3 years ago
6 0

Answer:

7x+8

Step-by-step explanation:

2(5x+4)-3x

distribute: 10x+8-3x

=7x+8

lorasvet [3.4K]3 years ago
5 0

Answer:

=7x+8

Step-by-step explanation:

Let's simplify step-by-step.

2(5x+4)−3x

Distribute:

=(2)(5x)+(2)(4)+−3x

=10x+8+−3x

Combine Like Terms:

=10x+8+−3x

=(10x+−3x)+(8)

=7x+8

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A rock concert promoter scheduled an outdoor concert on July 4th. If it does not rain, the promoter will make $30,427. If it doe
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For the probability of rain on julty 4h of 0.5 his expected profit is  8885.5 dollars.

<h3>What is probability?</h3>

The probability is occurrence of a certain event out of the total number f events that can happen.

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8 0
1 year ago
:) got to love math lol
zzz [600]
Oof im bad at math XD
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3 years ago
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(cotx+cscx)/(sinx+tanx)
Butoxors [25]

Answer:   \bold{\dfrac{cot(x)}{sin(x)}}

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)

\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)

\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}

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