A^8/a^3 hey can someone help me
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The option third is correct because nx(1-p)=2.6 less than equal to 10 then the sampling distribution is not approximate normal because p=0.87 is closer to 1 than zero.
Sampling distribution is skewed to the left.
It's the probability curve of a continuous distribution that's most likely symmetric around the mean. On the Z curve, at Z=0, the chance is 50-50. A bell-shaped curve is another name for it.
Because the requirement for normal is greater than 10, n×p is greater than 10 and nx(1-p) is also greater than 10.
This situation is abnormal because it is not valid. If p is close to 1 in a normal graph, then p is left skewed.
Thus, the option third is correct because nx(1-p)=2.6 less than equal to 10 then the sampling distribution is not approximate normal because p=0.87 is closer to 1 than zero. Sampling distribution
is skewed to the left.
Learn more about the normal distribution here:
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