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riadik2000 [5.3K]
1 year ago
12

Evaluate the following function when x = -1 and x = 2 and determine the sum of the two results:

Mathematics
1 answer:
ElenaW [278]1 year ago
7 0

Answer:

J. 1

Step-by-step explanation:

Plug the x values into the equation:

f(-1)=3-(-1)^2

f(2)=3-(2)^2

Solve each one, then add.

3-(-1)^2=

=3-1=2

3-(2)^2=

=3-4=-1

Combine the answers together.

2-1=1

The answer is J. 1.

Hope this helps!

Please mark as brainliest if correct!

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<img src="https://tex.z-dn.net/?f=%5Chuge%5Csf%5Cunderline%7BQuestion%7D" id="TexFormula1" title="\huge\sf\underline{Question}"
vekshin1

{\qquad\quad\qquad\huge\underline{{\sf Answer}}}

Here we go ~

\qquad \sf  \dashrightarrow \:  {x}^{2}  +  \cfrac{1}{ {x}^{2} }  = 34

[ add 2 on both sides ]

\qquad \sf  \dashrightarrow \:  {x}^{2}  +  \cfrac{1}{ {x}^{2} } + 2  = 34 + 2

[ form identity : a² + b² + 2ab ]

\qquad \sf  \dashrightarrow \:  {(x)}^{2}  +  { \bigg(\cfrac{1}{ {x}^{} } \bigg) }^{2}  + 2 \sdot(x)  \sdot  \bigg(\cfrac{1}{x} \bigg)  = 36

[ a² + b² + 2ab = (a + b)² ]

\qquad \sf  \dashrightarrow \: {\bigg (x  +  \cfrac{1}{x}  \bigg) }^{2}  = 36

\qquad \sf  \dashrightarrow \: {\bigg (x  +  \cfrac{1}{x}  \bigg) }^{}  =  \sqrt{ 36}

\qquad \sf  \dashrightarrow \: x  +  \cfrac{1}{x}    =   \pm 6

so, the value of required expression is 6

[usually positive value is considered, but if asked the value can be either positive or negative]

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