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2 years ago

Given an odd function, which of the following transformations would result in an odd function? Check all that apply.

Mathematics

1 answer:

professor190 [17]2 years ago

8 0

Answer:

Vertical stretch and reflection across the x axis

Step-by-step explanation:

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In a cohort of thirty graduating students, there are three different prizes to be awarded. if no student can receive more than o

eimsori [14]

prize1 and prize2 and prize3

30 x 29 x 28 = 24360

Answer: 24,360 different ways

7 0

2 years ago

If the measure of <3 is 117 degrees, what is the measure of <7?

V125BC [204]

Answer:

117

Step-by-step explanation:

The answer is 117 because angle 3 and 7 are corresponding so they have the same measure

Hope this helps dude ^-^

7 0

2 years ago

Read 2 more answers

If O is the center of the circle find x.

Over [174]

Answer:

x = 60°

Step-by-step explanation:

Angles on the circle formed by the same arc are congruent, then

∠ BDC = ∠ BAC = 50°

x = 180° - (70 + 50)° ← sum of angles in triangle = 180°

x = 180° - 120° = 60°

3 0

2 years ago

What is the equation of the following graph in vertex form?

kow [346]

Answer:

D) y = (x+1)^2

Step-by-step explanation:

Given the graph, the y-intercept is 1, and the x-intercept is -1. Only equation that works is D:

When we plug in x=-1:

y=(-1+1)^2

y=0

This is shown on the graph

When we plug in y=1:

1=(x+1)^2

1=x+1

0=x

x=0

This shows up on the graph

7 0

2 years ago

Square root of 144 X^7 Y^5

LekaFEV [45]

The first step to solving this is to factor out the first perfect square
$\sqrt{12^{2} x^{7} y^{5} }$
now factor out the second perfect square
$\sqrt{ 12^{2} x^{6} X x y^{5} }$
then factor out the second perfect square
$\sqrt{ 12^{2} x^{6} X x y^{4} X y}$
the root of a product is equal to the product of the roots of each factor
$\sqrt{ 12^{2} }$ $\sqrt{ x^{6} }$ $\sqrt{ y^{4} }$ $\sqrt{xy}$
reduce the index of the radical and exponent with 2 of the first square root
12 $\sqrt{ x^{6} }$ $\sqrt{ y^{4} }$ $\sqrt{xy}$
reduce the index of the radical and exponent with 2 of the second square root
12x³ $\sqrt{ y^{4} }$ $\sqrt{xy}$
reduce the index of the radical and exponent with 2 of the third square root
12x³y² $\sqrt{xy}$
this means that the correct answer to your question is 12x³y² $\sqrt{xy}$ .
let me know if you have any further questions
:)

4 0

3 years ago