Question

The leg of an isosceles triangle has a length 2x+4 and the base has length 3x. The

Answer 1

Answer:

$Base = 57$

Step-by-step explanation:

Given

$Length = 2x + 4$

$Base = 3x$

$Perimeter = 141$

Required

Determine the length of the base

The perimeter of an isosceles triangle is:

$Perimeter = 2*Length + Base$

$141 = 2 (2x + 4) + 3x$

$141 = 4x + 8 + 3x$

Collect Like Terms

$4x + 3x = 141 - 8$

$7x = 133$

Divide both sides by 7

$x = 19$

To get the base, we substitute 19 for x in $Base = 3x$

$Base = 3 * 19$

$Base = 57$