All categories

3 years ago

The leg of an isosceles triangle has a length 2x+4 and the base has length 3x. The

Mathematics

1 answer:

ikadub [295]3 years ago

4 0

Answer:

$Base = 57$

Step-by-step explanation:

Given

$Length = 2x + 4$

$Base = 3x$

$Perimeter = 141$

Required

Determine the length of the base

The perimeter of an isosceles triangle is:

$Perimeter = 2*Length + Base$

$141 = 2 (2x + 4) + 3x$

$141 = 4x + 8 + 3x$

Collect Like Terms

$4x + 3x = 141 - 8$

$7x = 133$

Divide both sides by 7

$x = 19$

To get the base, we substitute 19 for x in $Base = 3x$

$Base = 3 * 19$

$Base = 57$

You might be interested in

The perimeter of the triangle shown is 30 inches. What is the length of the longest side of the triangle

Simora [160]

Answer:

The length of the longest side of the triangle is 13 inches

Step-by-step explanation:

step 1

Find the value of x

we know that

The perimeter of triangle is equal to the sum of its three length sides

$P=x+(2x+3)+(4x-8)$

$P=(7x-5) \ in$

we have

$P=30\ in$

substitute

$30=(7x-5)$

solve for x

$7x=30+5\\7x=35\\x=5$

step 2

Find the length of the longest side of the triangle

Remember that in a right triangle, the longest side is the hypotenuse

(2x+3) is the longest side

substitute the value of x

$2(5)+3=13\ in$

4 0

3 years ago

Which is the correct classification of StartFraction 3 Over 8 EndFraction?

Sedaia [141]

Answer: the answer is rational number 0.375

Step-by-step explanation:

:D trust me it’s correct

3 0

4 years ago

Read 2 more answers

SHOW YOUR FORMULA AND SOLUTION

spayn [35]

Answer:

2500 kg

Step-by-step explanation:

Given:

• Force produced by the truck = F = 15,000 Newtons Acceleration of the truck = a = 6 m/s²

To find:

Mass of the truck if force is 15000 newtons and acceleration is 6 m/s²

Formula:

Force = Mass Acceleration

Substituting the above values:

15000N Mass×6

Mass = 15,000/6

Mass = 2500 kg

7 0

1 year ago

What is the difference in speed between two cars when one traveled 175 km in 4 hours and the other traveled the same distance in

vovangra [49]

<h3>Given :</h3>

Distance = 175
Time 1 = 4 hours

$\\ \\$

Different between two speeds when distance is same.

$\\ \\$

<h3>Solution:</h3>

In first part we will find speed 1 in which time is 4 hours

we know:-

$\bigstar \boxed{ \rm speed = \frac{distance}{time} }$

So:-

$\dashrightarrow\sf speed_1 = \dfrac{distance}{time_1}$

$\\ \\$

$\dashrightarrow\sf speed_1 = \dfrac{175}{4}$

$\\ \\$

$\dashrightarrow\bf speed_1 = 43.75 \: km {h}^{ - 1}$

In first part we will find speed 2 in which time is 3 hours

Again:

$\bigstar \boxed{ \rm speed = \frac{distance}{time} }$

$\\ \\$

$\dashrightarrow\sf speed_2 = \dfrac{distance}{time_2}$

$\\ \\$

$\dashrightarrow\sf speed_2 = \dfrac{175}{3}$

$\\ \\$

$\dashrightarrow\bf speed_2 = 58.33kmh^{-1}$

$\\ \\$

In this part we will find different between speed 1 and speed 2

$\bigstar \boxed{\rm Difference = speed_2 - speed_1}$

$\\ \\$

So :

$\dashrightarrow\sf Difference = speed_2 - speed_1 \\$

$\\ \\$

$\dashrightarrow\sf Difference =58.33 - 43.75\\$

$\\ \\$

$\dashrightarrow\bf Difference =14.58kmh^{-1}\\$

$\\ \\$

$\therefore \underline {\textsf{\textbf{Difference in speed between two cars is \red{14.58km/h}}}}$

4 0

3 years ago

WILL GIVE BRAINEST <br>if f(x)=2x-5 and g(x)=x2.....

Ymorist [56]

Note that the notation $(f+g)(x)$ is just another way of writing $f(x)+g(x)$ . Here, we're simply taking the expression for f(x) and adding the expression for g(x) to it. Together, we have:

$f(x)=2x-5\\g(x)=x^2-4x-8$

Which means that

$(f+g)(x)=f(x)+g(x)=(2x-5)+(x^2-4x-8)$

And from there, it's just a matter of combining like terms to simplify.

4 0

3 years ago