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IgorLugansk [536]
2 years ago
7

Whats the answer to 8h+5-3h=8h-4 and how do i do it

Mathematics
1 answer:
tiny-mole [99]2 years ago
5 0

The solution to the linear equation:

8h + 5 - 3h = 8h - 4

is h = 3.

<h3>How to solve the linear equation?</h3>

Here we have the linear equation:

8h + 5 - 3h = 8h - 4

To solve it, we need to move all the terms with h to the left side of the equation and the terms without x to the right side:

8h - 3h -8h = -4 - 5

-3h = -9

Now we can divide both sides by -3 to get:

h = -9/3 = 3

We conclude that the solution to the linear equation is h = 3.

If you want to learn more about linear equations:

brainly.com/question/1884491

#SPJ1

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xenn [34]
The answer is A so pick that
6 0
3 years ago
Question 10 multiple choice
vekshin1

Answer: Choice B

(x-1)(x^3+x^2+5x+6)

==========================================

Explanation:

The 1 in the upper left box means that x = 1 is a root of the original polynomial.

So this means x-1 is a factor of the original polynomial.

This is because x = 1 leads to x-1 = 0 after subtracting 1 from both sides.

-----------------

The 0 in the last position of the bottom row shows we got a remainder of 0.

Getting a remainder 0 tells us that (x-1) is a factor of the polynomial. This synthetic division table confirms our initial guess.

The other values in that bottom row (1, 1, 5, 6) form coefficients to the polynomial 1x^3+1x^2+5x+6, or simply x^3+x^2+5x+6

-------------------

So we know that (x-1) and (x^3+x^2+5x+6) are factors

Meaning that,

x^4+4x^2+x-6 = (x-1)(x^3+x^2+5x+6)

You can confirm this by expanding out the right hand side (distribution rule).

3 0
3 years ago
What is the following quotient -2 srt8 4+sqrt 12
mash [69]

\dfrac{-2\sqrt8}{4+\sqrt{12}}=\dfrac{-2\sqrt{4\cdot2}}{4+\sqrt{4\cdot3}}=\dfrac{-2\cdot\sqrt4\cdot\sqrt2}{4+\sqrt4\cdot\sqrt3}=\dfrac{-2\cdot2\sqrt3}{4+2\sqrt3}=\dfrac{-4\sqrt2}{2(2+\sqrt3)}=-\dfrac{2\sqrt2}{2+\sqrt3}\\\\\text{Use}\ (a+b)(a-b)=a^2-b^2\\\\=\dfrac{-2\sqrt2}{2+\sqrt3}\cdot\dfrac{2-\sqrt3}{2-\sqrt3}=\dfrac{-2\sqrt2(2-\sqrt3)}{2^2-(\sqrt3)^2}\\\\\text{Use distributive property and}\ \sqrt{a}\cdot\sqrt{b}=\sqrt{ab}\\\\=\dfrac{-4\sqrt2+2\sqrt6}{4-3}=\dfrac{2\sqrt6-4\sqrt2}{1}=2\sqrt6-4\sqrt2

3 0
3 years ago
is searching online for airline tickets. Two weeks​ ago, the cost to fly from to was ​250$. Now the cost is 330 ​$. What is the
borishaifa [10]

Answer:

Cost increases to $330.

The percent increase here would be:

= (New price - Old price )/ Old price

= (330 - 250) / 250

= 0.32

= 32%

Cost increases to $330 and charges $50 baggage fee

= (New price - Old price )/ Old price

= (330 + 50 - 250) / 250

= 0.52

= 52%

6 0
3 years ago
Find the missing side length please help!
Jobisdone [24]

Answer:

x = 25.4

Step-by-step explanation:

Recall: SOHCAHTOA

Reference angle = 48°

Hypotenuse = x

Adjacent = 17

Apply the trigonometric function, CAH, since the Adj and Hyp are involved

Thus:

Cos 48° = Adj/Hyp

Cos 48° = 17/x

x*Cos 48° = 17

x = 17/Cos 48°

x = 25.4061013 ≈ 25.4 (nearest tenth)

3 0
3 years ago
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