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2 years ago

14

population or sample, a survey of 1000 adults in the united states found that 12% take there vacation during the winter months

1 answer:

Genrish500 [490]2 years ago

8 0

Answer:38282

Step-by-step explanation:you add

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Solve: 92x + 1 = 93x – 2

vichka [17]

Answer:

x equals 3 :) if i helped, please give brainliest!

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Please help me solve -6 = 14 - z/3

dybincka [34]

Solve. -6 = 14 - z/3Subtract 14 from both sides

-20 = -z/3

Multiply -3 by both sides to get rid of the negative and 3 with the z.

z= 60

6 0

4 years ago

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Evaluate the integral. (remember to use absolute values where appropriate. Use c for the constant of integration.) 5 cot5(θ) sin

ozzi

$I=5\int \frac{cos^{4}\theta }{sin\theta }\times cos\theta d\theta \\\\I=5\int \left ( 1-sin^{2}\theta \right )^{2}\times \frac{cos\theta }{sin\theta }d\theta \\put\ \sin\theta =t\\\\dt=cos\theta d\theta \\\\I=5\int\frac{t^{4}+1-2t^{2}}{t}dt\ \ \ \ \ \ \ \ \ \ \because (a-b)^2=a^2+b^2-2ab\\\\I=5\left ( \int t^{3}dt + \int \frac{1}{t} -2\int t \right )dt$

by using the integration formula

we get,

$\\I=5\left ( \frac{t^{4}}{4} +logt -t^{2}\right )\\\\I=\frac{5}{4}t^{4}+5\log t-5t^{2}+c$

now put the value of t=\sin\theta in the above equation

we get,

$\int 5\cot^5\theta \sin^4\theta d\theta=\frac{5}{4}sin^{4}\theta+5\log \sin\theta - 5sin^{2} \theta+c$

hence proved

7 0

3 years ago

I’ll give points + brainalist for correct answer (:

sweet-ann [11.9K]

Answer:

C) 2

Step-by-step explanation:

Emma: Range = 8

Arianna: Range = 6

The difference in the range is 2 (8-6)

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3 years ago

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When josh planted his bean plant, it stood only 2 inches tall. Since then it has grown 3.25 inches every two weeks. Write the eq

inessss [21]

Answer:

y=3.25x+2

Step-by-step explanation:

Y is the total height after x weeks and since it has grown 3.25 inches per 2 weeks it would be 3.25x and add 2 because the initial height is 2 inches

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3 years ago