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3 years ago

What is the length of Line segment A C? Round to the nearest tenth.

Mathematics

1 answer:

Archy [21]3 years ago

3 0

Step-by-step explanation:

To find AC we use tan

tan ∅ = opposite / adjacent

From the question

15 is the opposite

AC is the adjacent

tan 55 = 15 / AC

AC = 15 / tan 55

AC = 10.503

<h3>AC is 11 to the nearest tenth </h3>

Hope this helps you

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Aliun [14]

Answer:

<em>The perimeter is 72 units and the area is 149 square units.</em>

Step-by-step explanation:

$\triangle SBA$ has coordinates $S(15,-8),B(-2,21)$ and $A(0,0)$

Using the distance formula.........

Length of side $SB = \sqrt{(15+2)^2+(-8-21)^2}= \sqrt{17^2+(-29)^2}= \sqrt{1130}$

Length of side $BA= \sqrt{(-2)^2+(21)^2}= \sqrt{445}$

Length of side $AS =\sqrt{(15)^2+(-8)^2}=\sqrt{289}=17$

So, the perimeter of the triangle will be: $(SB+BA+AS)= \sqrt{1130}+ \sqrt{445}+17 =71.71... \approx 72$ units. <em>(Rounded to the nearest unit)</em>

The height of the triangle for the corresponding base $SB$ is 8.89 units.

<u>Formula for the Area of triangle</u>, $A= \frac{1}{2}(base\times height)$

So, the area of the $\triangle SBA$ will be: $\frac{1}{2}(\sqrt{1130}\times 8.89)= 149.42... \approx 149$ square units. <em>(Rounded to the nearest unit)</em>

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Answer:

Step-by-step explanation:

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