Question

Solve the inequality 6h−5(h−1)≤7h−11 and write the solution in interval notation. Use improper fractions if necessary.

Answer 1

Answer:

$h \geq 2\frac{2}[3}$

Step-by-step explanation:

We solve the inequality similarly to how we would solve an equalitu.

$6h - 5(h-1) \leq 7h - 11$

$6h - 5h + 5 \leq 7h - 11$

$h - 7h \leq -11 - 5/$

$-6h \leq -16$

Multiplying everything by -1

$6h \geq 16$

Simplifying by 2

$3h \geq 8$

$h \geq \frac{8}{3}$

8 divided by 3 is 2 with rest two. So as a improper fraction, the answer is:

$h \geq 2\frac{2}[3}$