Answer:
24-(L times 2) then divide the awnser by 2
Step-by-step explanation:
Answer:
Gila Monster is 1.54 times that of Chuckwalla.
Step-by-step explanation:
Given:
Average Length of Gila Monster = 0.608 m
Average Length of Chuckwalla = 0.395 m
We need to find the number of times the Gila monster is as the Chuckwalla.
Solution:
Now we know that;
To find the number of times the Gila monster is as the Chuckwalla we will divide the Average Length of Gila Monster by Average Length of Chuckwalla.
framing in equation form we get;
number of times the Gila monster is as the Chuckwalla =
Rounding to nearest hundredth's we get;
number of times the Gila monster is as the Chuckwalla = 1.54
Hence Gila Monster is 1.54 times that of Chuckwalla.
You forgot to put the options and the rest of the equation
37.
13 - 7 = 6
Her Mom Uses 6
38.
9 + 8 = 17
Andrew Had 17 Muffins
Answer:
use the distance Formula D=sqrt of {(x1-x2)^2+(y1-y2)^2}
Step-by-step explanation:
So(-5--9)^2 + (-5- -2)^2 =
(4)^2 + (-3)^2 =
16 + 9 = 25
and the square root of 25 is 5.
5 is the answer