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2 years ago

11

A football team won 10 matches out of the total number of matches the great if their win percentage was 40 then how many matches

did they play in all.

2 answers:

Vlad [161]2 years ago

4 0

Answer:

they played 25 matches and win 10 and lose 15 matches

Free_Kalibri [48]2 years ago

3 0

Answer:

i draw it for you in the picture step by step

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Triangles PQR and RST are similar right triangles. Which proportion can be used to show that the slope of LaTeX: \overline{P

alukav5142 [94]

<em>Question:</em>

<em>Triangles PQR and RST are similar right triangles. Which proportion can be used to show that the slope of PR is equal to the slope of RT?</em>

Answer:

$\frac{3 - 7}{-4 - (-7)} = \frac{-5 - 3}{2 - (-4)}$

Step-by-step explanation:

See attachment for complete question

From the attachment, we have that:

$P = (-7,7)$

$Q = (-7,3)$

$R = (-4,3)$

$S = (-4,5)$

$T = (2,-5)$

First, we need to calculate the slope (m) of PQR

Here, we consider P and R

$m = \frac{y_2 - y_1}{x_2 - x_1}$

Where

$P(x_1,y_1) = (-7,7)$

$R(x_2,y_2) = (-4,3)$

$m = \frac{y_2 - y_1}{x_2 - x_1}$ becomes

$m = \frac{3 - 7}{-4 - (-7)}$ --------- (1)

Next, we calculate the slope (m) of RST

Here, we consider R and T

$m = \frac{y_2 - y_1}{x_2 - x_1}$

Where

$R(x_1,y_1) = (-4,3)$

$T (x_2,y_2)= (2,-5)$

$m = \frac{y_2 - y_1}{x_2 - x_1}$ becomes

$m = \frac{-5 - 3}{2 - (-4)}$ ---------- (2)

Next, we equate (1) and (2)

$\frac{3 - 7}{-4 - (-7)} = \frac{-5 - 3}{2 - (-4)}$

<em>From the list of given options (see attachment), option A answers the question</em>

4 0

2 years ago

6 people equally share bill rs 98.10 how

AnnZ [28]

Answer:

16.35Rs would be paid by everyone.

Step-by-step explanation:

98.10/6

=16.35Rs would be paid by everyone.

Hope it will help you :)

3 0

2 years ago

The quadratic function below has an axis of symmetry through x = -4; a vertex at (-4, -9) and zeroes at x = -7 and x = 0.

Pavlova-9 [17]

Answer:

True

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here (h, k) = (- 4, - 9), thus

y = a(x + 4)² - 9

To find a substitute the coordinates of the zero (- 7, 0) into the equation.

0 = a(- 7 + 4)² - 9, that is

0 = 9a - 9 ( add 9 to both sides )

9a = 9 ( divide both sides by 9 )

a = 1, thus

y = (x + 4)² - 9 ← expand factor using FOIL

y = x² + 8x + 16 - 9

y = x² + 8x + 7

4 0

2 years ago

I AWLAYS PROMISE BRAINLIEST ...... BRAINLEIST FOR THE CORRECT ASNWER

djyliett [7]

Answer:

<h3>its so hard im sorry i can't answer it</h3>

4 0

2 years ago

Read 2 more answers

If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.

Lelechka [254]

Answer:

$\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }$

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

$f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)$

So we can say that

$a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}$

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

$(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab$

and we can notice that

$a^2+b^2=(a+b)^2-2ab$ so

$(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab$

it comes

$x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}$

multiply by 3

$3x^2-20x+2*16+5=3x^2-20x+37$

4 0

3 years ago