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NARA [144]
1 year ago
6

George monitors the number of influenza infections reported in a certain neighborhood in a given week. The recent numbers are sh

own in this table:
Week Number of People
0 40
1 48
2 58
3 69

According to his reports, the reported infections are growing at a rate of 20%.

If the number of infections continues to grow exponentially, what will the number of infections be in week 8?
Mathematics
1 answer:
Rudik [331]1 year ago
5 0

The number of infections in week 8 will be 172 people

<h3>How to know an exponential table? </h3>

An exponential function is defined by the formula f(x) = aˣ, where the input variable x occurs as an exponent.

According to the reports, the reported infections are growing at a rate of 20%.

Therefore, the exponential function is as follows:

A = 40(1 + 20%)ⁿ

where

  • n = number of weeks

Hence,

Number people = 40(1 + 0.2)ⁿ

when n = 8 weeks

A = 40 (1 + 0.2)⁸

A = 40 (1.2)⁸

A = 40(4.29981696)

A = 171.9926784

A = 172

Therefore, the number of infections in week 8 is 172 people.

learn more on exponential table here: brainly.com/question/24832795

#SPJ1

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Answer:

Part 1) The polygon is a square

Part 2) The perimeter is equal to 20\ units

Part 3) The area is equal to 25\ units^{2}

Step-by-step explanation:

we have

A(5,0), B(2,4), C(-2,1),D(1,-3)

Plot the points

see the attached figure

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

A(5,0),B(2,4)

substitute in the formula

d=\sqrt{(4-0)^{2}+(2-5)^{2}}

d=\sqrt{(4)^{2}+(-3)^{2}}

d=\sqrt{25}

AB=5\ units

Find the distance BC

B(2,4), C(-2,1)

substitute in the formula

d=\sqrt{(1-4)^{2}+(-2-2)^{2}}

d=\sqrt{(-3)^{2}+(-4)^{2}}

d=\sqrt{25}

BC=5\ units

Find the distance CD

C(-2,1),D(1,-3)

substitute in the formula

d=\sqrt{(-3-1)^{2}+(1+2)^{2}}

d=\sqrt{(-4)^{2}+(3)^{2}}

d=\sqrt{25}

CD=5\ units

Find the distance AD

A(5,0),D(1,-3)

substitute in the formula

d=\sqrt{(-3-0)^{2}+(1-5)^{2}}

d=\sqrt{(-3)^{2}+(-4)^{2}}

d=\sqrt{25}        

AD=5\ units

we have that

AB=BC=CD=AD

Find the distance BD (diagonal)

B(2,4),D(1,-3)

substitute in the formula

d=\sqrt{(-3-4)^{2}+(1-2)^{2}}

d=\sqrt{(-7)^{2}+(-1)^{2}}

BD=\sqrt{50}\ units        

<em>Verify if the polygon is a square</em>

If the triangle BDA is a right triangle, then the polygon is a square

Applying the Pythagoras theorem

BD^{2}=AD^{2}+AB^{2}

substitute

(\sqrt{50})^{2}=5^{2}+5^{2}

50=50 -----> is true

so

The triangle BDA is a right triangle

therefore

The polygon is a square

<em>Find the Area of the polygon</em>

The area of a square is equal to

A=b^{2}

we have

b=5\ units

A=5^{2}=25\ units^{2}

<em>Find the perimeter of the polygon</em>

The perimeter of a square is equal to

P=4b

we have

b=5\ units

P=4(5)=20\ units

6 0
2 years ago
Determine the equation of a line that passrs through the point (4,-1) and also parallel to y=3x+4
nexus9112 [7]
First, plug in the given point into y=mx +b to find b (the y-intercept of the line). Use the same slope (m) in the equation since parallel lines have the same slope (3 in this case).

-1 = 3(4) +b
-1 = 12 + b Subtract 12 to both sides.
-13 = b

Now, put your m and b into y=mx+b.

The final answer/equation of your line is:

y=3x -13
5 0
3 years ago
Dilate (9, 6) using a scale factor of 1/3
KATRIN_1 [288]
The answer is (3,2)

To get this answer we either...
A) Multiply both coordinates by 1/3
or
B) Divide each coordinate by 3

9*(1/3) = 9/3 = 3
6*(1/3) = 6/3 = 2
6 0
3 years ago
A walkway is being constructed using square cement tiles that each have an area of 19.0 ft2. 6 tiles will be lined up end to end
allochka39001 [22]

Answer:

26.3 feet

Step-by-step explanation:

We have to first find the length of the side of each tile.

The area of each tile is 19.2 ft^2.

The area of a square is:

A = L^2

where L = length of side

Therefore:

19.2 = L^2\\\\L = \sqrt{19.2} =  4.38 feet

6 tiles will be lined end to end to construct the walkway, hence, the length of the walkway is:

6 * 4.38 ≅ 26.3 feet

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3 years ago
Sixty percent of those present at the performance were neophytes. If 200 present were not neophytes, how many people attended th
Marysya12 [62]

Answer:

450

Step-by-step explanation:

I do mental math. I think this is right if not then I am sorry

5 0
2 years ago
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