Answer:
10:30PM on the next day
Step-by-step explanation:
First movie = 85mins
intermission = 5mins
Total time = 90mins which is 1:30PM
so the first movie will start again at 1:30PM, which is at the interval of 90minutes and it will run continuously.
Similarly the second movie is 110 minutes long + 5mins intermission which is 115minutes
Time = 1:55PM
so the second movie starts again at 1:55PM and runs continuously at an interval of 115minutes.
We are interested to find when both the movie will start again at the same time, this will be least common multiple of 90 and 115.
LCM of 90,115 = 2070
Therefore after 2070minutes movie will start again at the same time.
2070mins = 34hours and 30 minutes
adding this with noon
10:30PM on the next day.
a) if the two gloves someone receives might both be for the left hand or right hand.
b) if each sister gets one left and one right.
Soln:
a) So i thought about dissectng the problem first into finding the number of ways in which I could make pairs of gloves:
C(12, 2)
then I asked how many ways could the sets of gloves be assigned amongst the 6 sisters:
<span><span>6!</span><span>6!</span></span>
and taking the product of this would give me the amount of ways this could occur:
= C(12,2) * 6!
then for part b)
using this same idea except:
C(6,1) C(6,1) for the left and right glove each .
the C(6,1)*C(6,1)*6!
Right way to think them through?
I think it’s x = 2
-20-12x+10=-34
-10-12x=34
-34+10
-24 divided by 12 = -2
Equation: bh
Equation: 6.2x2.4=14.88 inches^2
Answer:
A B C D F
Step-by-step explanation:
just did the assignment