<span>Think about which perfect squares lies on the immediate left of 52 and which lies on the immediate right of 52.
49 ---- 52 ------- 64
After that, take the square roots of each of the three numbers.</span>
Answer:
arithmetic sequence
Step-by-step explanation:
please mark as brainlist
Answer:
First the mode. Since 5 popped up the most, 5 is the mode.
Next is the median. I crossed 1 dot from each side until it shows the last dot, and 5 was the last one.
After that the range. 9-2=7
Finally the worst, the mean... 2+2+3+3+3+4+5+5+5+5+5+6+6+6+8+9+9+9+9
=104/19=5.47
SO, Mode=5 Median=5 Range=7, and the mean is 5.47 (rounded nearest hundred)
Answer:
The vertex is at (5,4).
Step-by-step explanation:
I graphed both of the functions on the graph below.
If this answer is correct, please make me Brainliest!
Answer:(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)
Step-by-step explanation:
We can rewrite left side into right side form
(x^2+y^2)^2=(x^2+y^2)(x^2+y^2)
we can expand it
(x^2+y^2)^2=x^4+x^2y^2+x^2y^2+y^4
(x^2+y^2)^2=x^4+y^4+2x^2y^2
we can add and subtract 2x^2y^2
(x^2+y^2)^2=x^4+y^4+2x^2y^2+2x^2y^2-2x^2y^2
(x^2+y^2)^2=x^4-2x^2y^2+y^4+2x^2y^2+2x^2y^2
(x^2+y^2)^2=x^4-2x^2y^2+y^4+4x^2y^2
(x^2+y^2)^2=x^4-2x^2y^2+y^4+(2xy)^2
(x^2+y^2)^2=(x^2-y^2)^2+(2xy)^2
