18 less than 14 times a is 80

The University of Ballygobackwards has three colleges: the College of Science, which has 12 staff, 8 of whom are female; the Col

IceJOKER [234]

Answer:

just split the awnser

Step-by-step explanation:

6 0

3 years ago

Due to a manufacturing error, two cans of regular soda were accidentally filled with diet soda and placed into a 18-pack. Suppos

crimeas [40]

Answer:

a) There is a 1.21% probability that both contain diet soda.

b) There is a 79.21% probability that both contain diet soda.

c) $P(X = 2)$ is unusual, $P(X = 0)$ is not unusual

d) There is a 19.58% probability that exactly one is diet and exactly one is regular.

Step-by-step explanation:

There are only two possible outcomes. Either the can has diet soda, or it hasn't. So we use the binomial probability distribution.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And $\pi$ is the probability of X happening.

A number of sucesses $x$ is considered unusually low if $P(X \leq x) \leq 0.05$ and unusually high if $P(X \geq x) \geq 0.05$

In this problem, we have that:

Two cans are randomly chosen, so $n = 2$

Two out of 18 cans are filled with diet coke, so $\pi = \frac{2}{18} = 0.11$

a) Determine the probability that both contain diet soda. P(both diet soda)

That is P(X = 2).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 2) = C_{2,2}(0.11)^{2}(0.89)^{0} = 0.0121$

There is a 1.21% probability that both contain diet soda.

b)Determine the probability that both contain regular soda. P(both regular)

That is P(X = 0).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 0) = C_{2,0}(0.11)^{0}(0.89)^{2} = 0.7921$

There is a 79.21% probability that both contain diet soda.

c) Would this be unusual?

We have that $P(X = 2)$ is unusual, since $P(X \geq 2) = P(X = 2) = 0.0121 \leq 0.05$

For P(X = 0), it is not unusually high nor unusually low.

d) Determine the probability that exactly one is diet and exactly one is regular. P(one diet and one regular)

That is P(X = 1).

$P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}$

$P(X = 1) = C_{2,1}(0.11)^{1}(0.89)^{1} = 0.1958$

There is a 19.58% probability that exactly one is diet and exactly one is regular.

8 0

3 years ago

Select the values that make the inequality - 4z > - 28 true. Then write an

Olenka [21]

Answer:

vyxkgxgjxufxruzfjzfjzf

gxiggxifxifx

xkzufxurzt
izifxur

7 0

3 years ago

What is the value of x?<br> x<br> 360<br> 22°

Yuri [45]

Answer:

x just represents a number

6 0

3 years ago

.

adell [148]

Answer:

$x + y = 1042$

$1.5x + 0.75y = 1140$

Step-by-step explanation:

This question can be solved by a system of equations.

I am going to say that:

x is the number of regular fares paid.

y is the number of reduced fares paid.

1,042 total fares were paid

This means that $x + y = 1042$

A city bus collected $1,140 in fares on a given day. The regular fare is $1.50, and the reduced fare is $0.75.

This means that:

$1.5x + 0.75y = 1140$

System of equations:

The system of equations is:

$x + y = 1042$

$1.5x + 0.75y = 1140$

4 0

3 years ago