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Wittaler [7]
2 years ago
7

Two sequences have the formulae 3n - 1 and 7n + 2. A new sequence is formed by the numbers which appear in both of these. Determ

ine the nth term of the new sequence.​
Mathematics
2 answers:
Jobisdone [24]2 years ago
5 0
Oh ya I can w it. Oh t no. Oh ya
Sonja [21]2 years ago
4 0

Answer:

Two sequences have the formulae 3n-1 and 7n+2 . A new sequences is formed by the number which appear in both of these sequences.

Step-by-step explanation:

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When you round a number, what should you do with the digits to the right of the place to which you are rounding?
kaheart [24]
Depends on what place you are rounding to. you would usually drop them
4 0
3 years ago
Read 2 more answers
Need help ASAP
madreJ [45]

Answer:

A 1/4

Step-by-step explanation:

2/3 x = 1/6

2x/3 = 1/6

2x/3 = 1/2x3

The answer  is 1/4

8 0
3 years ago
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Assume that the random variable X is normally distributed with mean u = 45 and standard deviation o = 14.
larisa86 [58]

Answer:

P(57 < X < 69) = 0.1513

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 45, \sigma = 14

Find P(57 < X < 69):

This is the pvalue of Z when X = 69 subtracted by the pvalue of Z when X = 57. So

X = 69

Z = \frac{X - \mu}{\sigma}

Z = \frac{69 - 45}{14}

Z = 1.71

Z = 1.71 has a pvalue of 0.9564

X = 57

Z = \frac{X - \mu}{\sigma}

Z = \frac{57 - 45}{14}

Z = 0.86

Z = 0.86 has a pvalue of 0.8051

0.9564 - 0.8051 = 0.1513

P(57 < X < 69) = 0.1513

4 0
3 years ago
How do i figure out problems like these
tiny-mole [99]

Answer:

look it up

Step-by-step explanation:

look it up and there you go

4 0
3 years ago
Determine whether y varies directly with x. If so, find the constant of variation.<br> Y=12x
Svet_ta [14]
<span>for y varies  directly with x, you should have y=kx  where k is constant of variation.ok</span>
6 0
3 years ago
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