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3 years ago

10

Ms. D's 4th period geometry class has both freshman and sophomores. There are 27 kids in the class and it has twice as many fres

hman as sophomores. How many freshman are in the class?
let x=
let y=

1 answer:

BARSIC [14]3 years ago

6 0

13.5 freshman well rounded off to 14 freshman

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The equation d=rt is used to calculate distance, rate, or time, where dd is the distance (in meters), r is the rate (in meters p

MAVERICK [17]

We know derrick walks 145 m/min to get the other we simply divide how far they went in how much time
Tomas: 1200/8= 150 m/min
Becky: 1400/10= 140m/min
therefore Tomas is the fastest walker so we will write the equation based on his speed
y = 150x
you should start at the origin (0,0) and got up 150 meters for and over 1 for every minute they run!

8 0

3 years ago

Read 2 more answers

Multiply the following rational expressions and simplify the result

GarryVolchara [31]

Answer:

Step-by-step explanation:

We have to solve the given expression,

$\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y}$

$\frac{9y-33y^2-3y^4}{100-49y^2}.\frac{7y^2+17y+10}{14y^2+28y}$ = $\frac{-y(-9+33y+3y^3)}{100-49y^2}.\frac{7y^2+17y+10}{14y(y+2)}$

= $\frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{7y^2+10y+7y+10}{14y(y+2)}$

= $\frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{y(7y+10)+1(7y+10)}{14y(y+2)}$

= $\frac{-y(-9+33y+3y^3)}{(10-7y)(10+7y)}.\frac{(y+1)(7y+10)}{14y(y+2)}$

= $\frac{-3y(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14y(y+2)}$

= $\frac{-3(-3+11y+y^3)}{(10-7y)}.\frac{(y+1)}{14(y+2)}$

= $\frac{3(3-11y-y^3)(y+1)}{(10-7y)(14(y+2)}$

3 0

3 years ago

25 - 4x = 15 - 3x + 1 - x

kenny6666 [7]

Hello!

To solve algebraic equations, we need to first, simplify the common terms, and secondly use SADMEP. SADMEP is strictly used to solve algebraic equations, and is used like PEMDAS. SADMEP is an acronym for subtract, addition, division, multiplication, exponents, and parentheses.

25 - 4x = 15 - 3x + 1 - x (simplify the common terms)

25 - 4x = 16 - 4x (subtract 16 from both sides)

9 - 4x = -4x (add 4x to both sides)

9 = 0 → This means that there is no solutions.

Therefore, this equation has no solutions, which are contradictions because those are the equations with no solution.

3 0

3 years ago

My sister can walk from school to home in 35 minutes. I can walk from school to home in 20 minutes. But today I stayed for some

Verizon [17]

Answer:

you both will reach the home at the same time.

I) You can catch your sister.

ii) Reason: you both will reach home at the same time.

Step-by-step explanation:

Let "d" be distance from school to home.

Let's find the speed of you and your sister.

Speed = $\frac{Distance}{Time}$

Your speed = $\frac{d}{20}$

Your sister's speed = $\frac{d}{35}$

Today, You stayed for some extra help by the time your sister covered $\frac{3}{7}$ of the way home.

Remaining distance to reach the home = $1 - \frac{3}{7}d = \frac{7-3}{7}d = \frac{4}{7}d$

=

Now let's find the time to be taken your sister to reach the home.

Time = $\frac{distance}{speed}$

= $\frac{\frac{4}{7}d }{\frac{1}{35} d} = \frac{4}{7} *\frac{35}{1} = 20$

So, your sister will take 20 minutes to get home by the time your start.

We know that it takes you 20 minutes to reach your home.

Therefore, you both will reach the home at the same time.

I) You can catch your sister.

ii) Reason: you both will reach home at the same time.

7 0

3 years ago

Match the phenomenal expression on the left with the simplified version on the right

nalin [4]

Given the polynomial expression:

(y + 5)²

(y - 5)(y + 5)

Let's simplify each of the given expression:

a.) (y + 5)²

The given equation is a factor of a perfect square trinomial. For this type of expression, the following is the formula for expanding it.

$\text{ (a+b)}^2\text{ = }a^2\text{ + 2ab + }b^2$

We get,

$\mleft(y+5\mright)^2=(y)^2+2(y)(5)+(5)^2$ $(y+5)^2=y^2+10y+25$

b.) (y - 5)(y + 5)

To be able to simplify the following expression. We will be using the formula for the difference of two squares.

$(a+b)(a-b)=a^2-b^2$

We get,

$\mleft(y-5\mright)\mleft(y+5\mright)=(y)^2-(5)^2$ $(y-5)(y+5)=y^2-25^{}$

8 0

1 year ago