Answer:
if there are 360 students, the number of teacher will be 6,480...
360:6,480
Anything raised to exponent 0 equals 1
So

So we get

Answer:
The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of
.
Step-by-step explanation:
The formula from the maximum distance of a projectile with initial height h=0, is:

Where
is the initial velocity.
In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is
. The critical points of the function are those who make
:


The critical value inside the interval is
.

The second step is to find the values of the function at the endpoints of the interval:

The biggest value of f is gived by
, therefore
is the absolute maximum.
In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of
.
Answer:
B
Step-by-step explanation:
it is B because i dont know how to explain it but just look at it very closely and then look back
Answer:

Step-by-step explanation:
Hello!
We can solve the quadratic by using the quadratic formula.
Standard form of a quadratic: 
Quadratic Formula: 
Given our Equation: 
Plug the values into the equation and solve.
<h3>Solve</h3>