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Triss [41]
2 years ago
15

Help me please❥ ❥ ❥ ❥ ❥ ❥ ❥ ❥ ❥ ❥ ❥ ❥ ❥

Mathematics
1 answer:
VLD [36.1K]2 years ago
5 0

21

Step-by-step explanation:

m=5n=2

5-2=3

5×2=10

5²-2²=

25-4=21

hope it helps

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P=3y/q solve for y make sure to add steps pls
Likurg_2 [28]

Answer:

Solving for y gives:

y = \frac{pq}{3}

Step-by-step explanation:

Linear equations are the equations that are degree one equations. When it is asked to solve an equation for a specific variable that means that the specified variable has to be isolated on one side of the equation i.e. in the given question solving for y means isolating y on one side of the equation.

Given equation is:

p = \frac{3y}{q}

Multiplication property of equality(Multiplying both sides by q)

p*q = \frac{3y}{q} * q\\pq = 3y

Division property of equality(Dividing both sides by 3)

\frac{pq}{3} = \frac{3y}{3}\\\frac{pq}{3} = y

Hence,

Solving for y gives:

y = \frac{pq}{3}

7 0
3 years ago
PLS HELP ASAP THANKS ILL GIVE BRAINLKEST PLS THANKS PLS ASAP
nikklg [1K]

Answer:

LN and RQ

Step-by-step explanation:

PQR is just an enlargened version of MLN

RQ is just LN but longer

7 0
3 years ago
Read 2 more answers
What is the equation of a line, in point-slope form, that passes through (-4, -1) and has a slope of (5, 7)
bearhunter [10]

It is y+1=0.9(x+4) because the formula is y - y1=m(x + x1) you only need one point and the slope. If you have two points, you need to find the slope by using the slope formula slope=y2-y1/x2-x1. Filling it in it would look like slope=7-(-1)/5-(-4). The double negatives cancel each other out and it turns to addition signs leaving us with slope=7+1/5+4 so the slope is 8/9 or 0.9. Now you can fill out the point-slope formula y+1=0.9(x+4)

8 0
3 years ago
Read 2 more answers
Use the ruler provided to measure the dimensions of the parallelogram shown to the nearest ½ centimeter.
In-s [12.5K]

Answer:

Enduring Understandings:

The square roots of perfect squares are rational numbers.

The square roots of non-perfect squares are irrational numbers.

Many geometric properties and attributes of shapes are related to

measurement.

General Learning Outcomes:

Develop number sense.

Use direct or indirect measurement to solve problems.

Specific Learning Outcome(s): Achievement Indicators:

8.N.1 Demonstrate an understanding

of perfect squares and square

roots, concretely, pictorially, and

symbolically (limited to whole

numbers).

[C, CN, R,V]

 Represent a perfect square as a square

region using materials, such as grid paper

or square shapes.

 Determine the factors of a perfect square,

and explain why one of the factors is the

square root and the others are not.

 Determine whether or not a number is

a perfect square using materials and

strategies such as square shapes, grid paper,

or prime factorization, and explain the

reasoning.

 Determine the square root of a perfect

square, and record it symbolically.

 Determine the square of a number.

8.N.2 Determine the approximate

square root of numbers that are

not perfect squares (limited to

whole numbers).

[C, CN, ME, R, T]

 Estimate the square root of a number that

is not a perfect square using the roots of

perfect squares as benchmarks.

 Approximate the square root of a number

that is not a perfect square using technology

(e.g., calculator, computer).

continued

4 Grade 8 Mathematics: Suppor t Document for Teachers

Specific Learning Outcome(s): Achievement Indicators:

 Explain why the square root of a number

shown on a calculator may be an

approximation.

 Identify a number with a square root that is

between two given numbers.

8.SS.1 Develop and apply the

Pythagorean theorem to solve

problems.

[CN, PS, R, T, V]

 Model and explain the Pythagorean

theorem concretely, pictorially, or by using

technology.

 Explain, using examples, that the

Pythagorean theorem applies only to

right triangles.

 Determine whether or not a triangle

is a right triangle by applying the

Pythagorean theorem.

 Solve a problem that involves determining

the measure of the third side of a right

triangle, given the measures of the other

two sides.

 Solve a problem that involves Pythagorean

triples (e.g., 3, 4, 5 or 5, 12, 13).

Prior Knowledge

Students may have had experience with the following:

Q Demonstrating an understanding of regular and irregular 2-D shapes by

Q recognizing that area is measured in square units

Q selecting and justifying referents for the units cm² or m²

Q estimating area by using referents for cm² or m²

Q determining and recording area (cm² or m²)

Q constructing different rectangles for a given area (cm² or m²) in order to

demonstrate that many different rectangles may have the same area

Q Solving problems involving 2-D shapes and 3-D objects

Q Designing and constructing different rectangles given either perimeter or area, or

both (whole numbers), and drawing conclusions

Q Identifying and sorting quadrilaterals, including

Q rectangles

Number 5

Q squares

Q trapezoids

Q parallelograms

Q rhombuses

according to their attributes

Q Developing and applying a formula for determining the

Q perimeter of polygons

Q area of rectangles

Q volume of right rectangular prisms

Q Constructing and comparing triangles, including

Q scalene

Q isosceles

Q equilateral

Q right

Q obtuse

Q acute

in different orientations

Background Information

Squares and Square Roots

A square is a 2-dimensional (2-D) shape with all four sides equal.

The total area the square covers is measured in square units.

To determine the side length of a square when given the area, the square root must be

determined.

A perfect square can be described as

Q a square with whole number sides (e.g., 1 × 1, 2 × 2, 3 × 3)

Q a number whose square root is an integer (e.g., 4 = 2 or –2)

A non-perfect square can be described as

Q a square with non-whole number sides (e.g., 1.2 × 1.2)

Q a number whose square root is not a whole number (e.g., 2)

Rounding is often used to determine the approximate square root of non-perfect

squares.

Step-by-step explanation:

7 0
3 years ago
The smallest object visible with your eyes is similar to the width of a piece of hair, which is 1×10−4 meters wide. Using an opt
Sloan [31]

Answer:

B. 5\times10^{2}

Step-by-step explanation:

We are told that the smallest object visible with our eyes is similar to the width of a piece of hair, which is 1\times 10^{-4} meters wide.

Using an optical microscope, we can see items up to 2\times 10^{-7} meters wide.

To find the objects we can see with our eyes are how much larger than the objects we can see with an optical microscope, we can set an equation as:

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=\frac{1*10^{-4}}{2*10^{-7}}

Using the exponent rule of quotient \frac{a^m}{a^n}=a^{m-n} we will get,

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=\frac{1}{2}*10^{-4-(-7)}

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10^{-4+7}

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10^{3}

\frac{\text{The width of the object we can see with our eyes}}{\text{The width of the objects we can see with microscope}}=0.5*10\times 10^{3-1}

\text{The object we can see with our eyes}=5\times10^{2}*\text{The objects we can see with microscope}

Therefore, the objects we can see with our eyes are 5\times10^{2} times larger than the objects we can see with an optical microscope and option B is the correct choice.

3 0
3 years ago
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