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2 years ago

HELP THIS IS DUE TODAY!!!!!! AHHHHHH

Mathematics

1 answer:

belka [17]2 years ago

8 0

Answer:

260 / 5 = 52

Step-by-step explanation:

give brainliest please

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Can someone please help me. I need help on the 5 one

soldi70 [24.7K]

Answer:

The second option

Step-by-step explanation:

On the right hand side you have all the multiples of 4, on the left hand side you have 5

The multiples of four are ...,-8,-4,0,4,8,....

so the simbol that means that 5 is not an element of the multiples of four is the second option.

4 0

2 years ago

What is it mean? <br> a. 27.19 <br> b. 27.29 <br> c. 28.10 <br> d. 28.11

Len [333]

Mean is average so you sum up all 4 numbers and divide by 4. Answer is 27.6725 or rounded 27.67

Have a nice day. Hope this helps.

3 0

1 year ago

How do you times fraction by whole numbers

ehidna [41]

To multiply whole numbers and fractions, multiply the numerator by the whole number. Example: 1/3×4= 4/3=1 1/3

5 0

2 years ago

Read 2 more answers

What is 67/7 as mixed number

monitta

Answer:

9 4/7

Step-by-step explanation:

First, we need to make as many 7s as possible. If we do 67/7, we will get 9...... so our whole number is 9. If we do 7 x 9, we get 63 and if we subtract 63 from 67, we are left with 4. All in all, we will get 9 4/7!

6 0

3 years ago

Match each interval with its corresponding average rate of change for q(x) = (x + 3)2. 1. -6 ≤ x ≤ -4 1 2. -3 ≤ x ≤ 0 -4 3. -6 ≤

MrMuchimi

The average rate of change of a function f(x) in an interval, a < x < b is given by
$\frac{f(b) - f(a)}{b - a}$

Given q(x) = (x + 3)^2

1.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -4 is given by $\frac{q(-4)-q(-6)}{-4-(-6)} = \frac{(-4+3)^2-(-6+3)^2}{-4+6} = \frac{1-9}{2} = \frac{-8}{2} =-4$

2.) The average rate of change of q(x) in the interval -3 ≤ x ≤ 0 is given by $\frac{q(0)-q(-3)}{0-(-3)} = \frac{(0+3)^2-(-3+3)^2}{0+3} = \frac{9-0}{3} = \frac{9}{3} =3$

3.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-6)}{-3-(-6)} = \frac{(-3+3)^2-(-6+3)^2}{-3+6} = \frac{0-9}{3} = \frac{-9}{3} =-3$

4.) The average rate of change of q(x) in the interval -3 ≤ x ≤ -2 is given by $\frac{q(-2)-q(-3)}{-2-(-3)} = \frac{(-2+3)^2-(-3+3)^2}{-2+3} = \frac{1-0}{1} = \frac{1}{1} =1$

5.) The average rate of change of q(x) in the interval -4 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-4)}{-3-(-4)} = \frac{(-3+3)^2-(-4+3)^2}{-3+4} = \frac{0-1}{1} = \frac{-1}{1} =-1$

6.) The average rate of change of q(x) in the interval -6 ≤ x ≤ 0 is given by $\frac{q(0)-q(-6)}{0-(-6)} = \frac{(0+3)^2-(-6+3)^2}{0+6} = \frac{9-9}{6} = \frac{0}{6} =0$

3 0

2 years ago

Read 2 more answers