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3 years ago

HELP THIS IS DUE TODAY!!!!!! AHHHHHH

Mathematics

1 answer:

belka [17]3 years ago

8 0

Answer:

260 / 5 = 52

Step-by-step explanation:

give brainliest please

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What is the simplified form of the complex fraction? 2x2+7x+6x2+x−64x2−9x2−5x+6

kiruha [24]

Answer:

3x - 124

Step-by-step explanation:

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3 years ago

Simplify this algebraic expression completely. 6x – 4(x + 3)

Arturiano [62]

6x - 4(x + 3)
6x -4x -12. Distribute
2x - 12. Combine like terms

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3 years ago

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Don't know how to do this simplify each expression by combining terms

Ilya [14]

Answer:

Combining like terms is actually pretty straightforward, you just have to combine like terms. In the problem 5c+2c, it would equal 7c since c is a common variable in this equation.

In the next question 16p+5+p-3x+6-x, it would equal 17p-4x+11 because 16p+p is 17p, -3x-x is -4x, and 5+6 equals to 11.

In the third question 18p+3-8p-5 would equal to 10p-2 since 18p-8p equals to 10p, and 3-5 equals to -2.

In the last question 9u+11v-22u+12v, it would equal to -13u+23v because 9u-22u equals to -13, and 11v+12v is 23v.

I hope this helped you!

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3 years ago

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How many solutions does the system have? y=−2x+4

Anna11 [10]

Answer:

There is only one solution and the solution is (0,4).

Step-by-step explanation:

The given system has equations;

$y=-2x+4$

and

$y=x^2-2x+4$

We equate the two equations to determine their point of intersection;

$x^2-2x+4=-2x+4$

$\Rightarrow x^2-2x+2x+4-4=0$

$\Rightarrow x^2=0$

$\Rightarrow x=0$

We put x=0 into the first equation to get;

$y=-2(0)+4=4$

There is only one solution and the solution is (0,4).

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3 years ago

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Solve the simultaneous equations y = 9 - X y = 2x2 + 4x + 6

kenny6666 [7]

Answer:

$\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=9-x,\:y=2x^2+4x+6\mathrm{\:are\:}$

$\begin{pmatrix}x=\frac{1}{2},\:&y=\frac{17}{2}\\ x=-3,\:&y=12\end{pmatrix}$

Step-by-step explanation:

Given the simultaneous equations

$y=9-x$

$y\:=\:2x^2\:+\:4x\:+\:6$

Subtract the equations

$y=9-x$

$-$

$\underline{y=2x^2+4x+6}$

$y-y=9-x-\left(2x^2+4x+6\right)$

$\mathrm{Refine}$

$x\left(2x+5\right)=3$

$\mathrm{Solve\:}\:x\left(2x+5\right)=3$

$2x^2+5x=3$ ∵ $\mathrm{Expand\:}x\left(2x+5\right):\quad 2x^2+5x$

$\mathrm{Subtract\:}3\mathrm{\:from\:both\:sides}$

$2x^2+5x-3=3-3$

$\mathrm{Solve\:with\:the\:quadratic\:formula}$

$\mathrm{Quadratic\:Equation\:Formula:}$

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=2,\:b=5,\:c=-3:\quad x_{1,\:2}=\frac{-5\pm \sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}v\\$

$x=\frac{-5+\sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}$

$=\frac{-5+\sqrt{5^2+4\cdot \:2\cdot \:3}}{2\cdot \:2}$

$=\frac{-5+\sqrt{49}}{2\cdot \:2}$

$=\frac{-5+\sqrt{49}}{4}$

$=\frac{-5+7}{4}$

$=\frac{2}{4}$

$=\frac{1}{2}$

Similarly,

$x=\frac{-5-\sqrt{5^2-4\cdot \:2\left(-3\right)}}{2\cdot \:2}:\quad -3$

$\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}$

$x=\frac{1}{2},\:x=-3$

$\mathrm{Plug\:the\:solutions\:}x=\frac{1}{2},\:x=-3\mathrm{\:into\:}y=9-x$

$\mathrm{For\:}y=9-x\mathrm{,\:subsitute\:}x\mathrm{\:with\:}\frac{1}{2}:\quad y=\frac{17}{2}$

$\mathrm{For\:}y=9-x\mathrm{,\:subsitute\:}x\mathrm{\:with\:}-3:\quad y=12$

$\mathrm{Therefore,\:the\:final\:solutions\:for\:}y=9-x,\:y=2x^2+4x+6\mathrm{\:are\:}$

$\begin{pmatrix}x=\frac{1}{2},\:&y=\frac{17}{2}\\ x=-3,\:&y=12\end{pmatrix}$

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4 years ago