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2 years ago

8

Hey guys! Sorry to bother but I need help with these. 5th grade math, will give brainliest! (If you see multiple questions by me

that look the same, they are all different.)

1 answer:

-Dominant- [34]2 years ago

7 0

Answer:

Question 3: 1/15 Question 4: 50

Step-by-step explanation:

Just divide the fractions by the numbers.

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What percent of 84 is 21

dlinn [17]

25% because 21 is a quarter of 84. And 21 times 4= 84, so 21 is 25% of 84.

6 0

2 years ago

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there are 12 teams in the jayhook hockey league each team plays every other team twice per season, once at home and once away. L

Gre4nikov [31]

Answer:

58

Step-by-step explanation:

As there are 12 teams in the league and each teams plays every other team twice per season. so, the total number of matches in the league will be 132.

let the matches won by home team = 'x'

given,

number of matches drawn = 34

matches won by the away team = x - 18

Now, according to the question,

⇒ total matches = matches drawn + matches won by home team + matches won by away team

⇒ 132 = 34 + x + x -18

⇒ x = 58

5 0

2 years ago

There are 257 people at a dance performance. Orchestra seats cost $12 and balcony seats cost $8. The total receipts were $2,716.

solniwko [45]

x = # of balcony seats

y = # of orchestra seats

We have to create a system of equations to solve this problem

x + y = 256

$8x + $12y = $2,716

We will solve this system of equations by elimination.

Multiply the first equation by -8

-8x - 8y = -2048

8x + 12y = 2716

Let's add the equations together

0 + 4y = 668

Simplify the left side

4y = 668

Divide both sides by 4

y = 167

We can subtract 167 from 257 to get the number of balcony seats.

257 - 167 = 90 balcony seats

There are 167 orchestra seats and 90 balcony seats

5 0

2 years ago

A professor finds that the average SAT score among all students attending his college is 1150 ± 150 (μ ± σ). He polls his class

solniwko [45]

Answer:

Step-by-step explanation

Hello!

Be X: SAT scores of students attending college.

The population mean is μ= 1150 and the standard deviation σ= 150

The teacher takes a sample of 25 students of his class, the resulting sample mean is 1200.

If the professor wants to test if the average SAT score is, as reported, 1150, the statistic hypotheses are:

H₀: μ = 1150

H₁: μ ≠ 1150

α: 0.05

$Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~~N(0;1)$

$Z_{H_0}= \frac{1200-1150}{\frac{150}{\sqrt{25} } } = 1.67$

The p-value for this test is 0.0949

Since the p-value is greater than the level of significance, the decision is to reject the null hypothesis. Then using a significance level of 5%, there is enough evidence to reject the null hypothesis, then the average SAT score of the college students is not 1150.

I hope it helps!

7 0

2 years ago

What is the answer to 2(9x+12) A.18x+12 B.18x+24 C.9x+24

LUCKY_DIMON [66]

2(9x) +2(12)= 18x + 24

6 0

3 years ago

Read 2 more answers