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True [87]
1 year ago
10

What is the slope of the line that passes through the points (-8,-1) and (-8,11)?

Mathematics
1 answer:
lubasha [3.4K]1 year ago
4 0

Answer: \text{Slope}=\Large\boxed{Unde fined}

Step-by-step explanation:

<u>Given information</u>

(x_1,~y_1)=(-8,~-1)

(x_2,~y_2)=(-8,~11)

<u>Given the formula for the slope</u>

\text{Slope}=\dfrac{\Delta y}{\Delta x}=\dfrac{y_2-y_1}{x_2-x_1}

<u>Substitute values into the formula</u>

\text{Slope}=\dfrac{(11)-(-1)}{(-8)-(-8)}

<u>Simplify the numerator and the denominator</u>

\text{Slope}=\dfrac{11+1}{-8+8}

\text{Slope}=\dfrac{12}{0}

<u />

<u>Simplify the fraction</u>

\text{Since any number divided by 0 is impossible to find, therefore: }

\text{Slope}=\Large\boxed{Unde fined}

Hope this helps!! :)

Please let me know if you have any questions

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Find slope of the graph 9x-3y=15
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<h3><u>Explanation</u></h3>
  • Convert the equation into slope-intercept form.

y = mx + b

where m = slope and b = y-intercept.

What we have to do is to make the y-term as the subject of equation.

9x - 3y = 15 \\ 9x - 15 = 3y \\  \frac{9x - 15}{3}  = y

  • Simplify

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<h3><u>Answer</u></h3>

\large \boxed {slope = 3}

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