Express 2x^2+8x+3 in the form 2(x+p)^2+q
1 answer:
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Answer:
<u>Step 1: Set x to 0 </u>
(0, 3)
<u>Step 2: Set x to 1 </u>
(1, 5)
<u>Step 3: Set x to 2 </u>
(2, 7)
<u>Step 4: Set x to 3 </u>
(3, 9)
Answer:
(See step-by-step)
Step-by-step explanation:
Let’s start by making A-(X) and W-(Y). So, when substituting the variables you get x=210-35y. When x=0, the answer to the equation is 6. So, the y-intercept (when x=0) is 6 or (0,6). When y=0, the answer to the equation/x-intercept(y=0) is 210 or (210,0). The graph itself looks like the image included.
The domain, realistically, is x>=0 however on the graph itself, the domain is x= All Real Numbers. The range realistically is y>=0, but on the graph it is also All Real Numbers.
The x-intercept is the account when no weeks have passed and no money is lost (210) and the y-intercept is the maximum amount of weeks before there is no more money in the account (6).
