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Blizzard [7]
3 years ago
6

A fair coin and a biased coin where the probability of obtaining a head is twice the probability of obtaining a tail. if both ar

e tossed simultaneously, find the probability that they are:
a) both heads
b) both tails
c) one head
d) at least one head
Mathematics
1 answer:
Art [367]3 years ago
4 0

Answer:

See below in bold.

Step-by-step explanation:

For the fair coin Prob(head) = 1/2 and Prob(Tail) = 1/2.

For the biased coin it is   Prob(head) = 2/3 and Prob(Tail) = 1/3.

a) Prob(2 heads) = 1/2 * 2/3 = 1/3.

b) Prob(2 tails) = 1/2 * 1/3 = 1/6.

c) Prob(1 head ) = Prob(H T or T H) = 1/2 * 1/3  + 1/2 * 2/3) = 1/6+1/3 = 1/2.

d) Prob (at least one head) = prob (HH or TH or HT) =  1/3 + 1/2 =<em> </em>5/6.

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Answer:

y = \dfrac{1}{3}x + 1

Step-by-step explanation:

The given line is in slope-intercept form,

y = mx + b,

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The slope of the given line is 1/3, so m = 1/3.

Parallel lines have equal slopes, so the slope of the parallel line is also 1/3.

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Now we can find the equation of the parallel line through point (6, 3) by using the given point's coordinates for x and y and solving for b.

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