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3 years ago

I really need help with this pleaseeee

Mathematics

1 answer:

Sedaia [141]3 years ago

4 0

Answer:

σ = 11.68

Step-by-step explanation:

$σ = \sqrt{ \frac{Σ{(xi - μ)}^{2} }{N} } \\ where \: σ = population \: standard \: deviation \\ xi = each \: value \: from \: population \\ μ = population \: mean \\ N = size \: of \: population$

$σ = \sqrt{ \frac{Σ{(9 - 26)}^{2} + {(16 - 26)}^{2} +{(30 - 26)}^{2} +{(35 - 26)}^{2} + {(40 - 26)}^{2}}{5} } \\ σ = \sqrt{ \frac{Σ{((-17)}^{2} + {(- 10) }^{2} +{(4) }^{2} +{(9) }^{2} +{(14) }^{2})}{5}} \\ σ = \sqrt{ \frac{Σ ({289} + {100} +{16} +{81} + {196})}{5} } \\ σ = \sqrt{ \frac{682}{5} } \\ σ = \sqrt{136.4} \\ σ = 11.679041056525\\ σ = 11.68$

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3 years ago

A line is drawn on a coordinate grid by the equation y = 4. Which of the following lines would represent a row parallel to it?

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2 years ago

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Usando el teorema de altura

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3 years ago

Assume that a company hires employees on Mondays, Tuesdays, or Wednesdays with equal likelihood.a. If two different employees ar

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Answer:

$P(A) = \frac{1}{9}$

$P(B) = \frac{1}{3}$

$P(C) = \frac{1}{729}$

Step-by-step explanation:

We know that:

Only employees are hired during the first 3 days of the week with equal probability.

2 employees are selected at random.

So:

A. The probability that an employee has been hired on a Monday is:

$P(M) = \frac{1}{3}$ .

If we call P(A) the probability that 2 employees have been hired on a Monday, then:

$P(A) =P(M\ and\ M)\\\\P(A)=( \frac{1}{3})(\frac{1}{3})\\\\P(A) = \frac{1}{9}$

B. We now look for the probability that two selected employees have been hired on the same day of the week.

The probability that both are hired on a Monday, for example, we know is $P(A) = \frac{1}{9}$ . We also know that the probability of being hired on a Monday is equal to the probability of being hired on a Tuesday or on a Wednesday. But if both were hired on the same day, then it could be a Monday, a Tuesday or a Wednesday.

$P(B) = \frac{1}{9} + \frac{1}{9} + \frac{1}{9}\\\\P(B) = \frac{1}{3}$ .

C. If the probability that two people have been hired on a specific day of the week is $3(\frac{1}{3}) ^ 2$ , then the probability that 7 people have been hired on the same day is:

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D. The probability is $\frac{1}{729}$ . This number is quite close to zero. Therefore it is an unlikely bastate event.

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3 years ago