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Virty [35]
3 years ago
13

I really need help with this pleaseeee

Mathematics
1 answer:
Sedaia [141]3 years ago
4 0

Answer:

σ = 11.68

Step-by-step explanation:

σ =  \sqrt{ \frac{Σ{(xi -  μ)}^{2} }{N} } \\ where \: σ = population \: standard \: deviation \\ xi = each \: value \: from \: population \\  μ = population  \: mean \\ N = size \: of \: population

σ =  \sqrt{ \frac{Σ{(9 - 26)}^{2} + {(16 - 26)}^{2} +{(30 - 26)}^{2} +{(35 - 26)}^{2} + {(40 - 26)}^{2}}{5} } \\ σ =  \sqrt{ \frac{Σ{((-17)}^{2} + {(- 10) }^{2} +{(4) }^{2} +{(9) }^{2} +{(14) }^{2})}{5}} \\ σ =  \sqrt{ \frac{Σ ({289} + {100} +{16} +{81} + {196})}{5} } \\ σ =  \sqrt{ \frac{682}{5} }  \\ σ  =  \sqrt{136.4} \\  σ = 11.679041056525\\ σ = 11.68

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Answer:

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Step-by-step explanation:

1) -20 divided by -4

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4) -2 plus 9

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3 years ago
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Rzqust [24]
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Nataliya [291]
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3 years ago
n a particular day, the wind added 2 miles per hour to Alfonso's rate when he was cycling with the wind and subtracted 2 miles p
goldfiish [28.3K]
Recall your d = rt, or distance = rate * time

notice, the time he took to cover 63 miles with the wind, is the same amount of time he took against it with 51 miles only, let's say, he took "t" hours long
and he was cycling at a rate of "r"

thus    \bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{with the wind}&63&r+2&t\\
\textit{against the wind}&51&r-2&t
\end{array}\\\\
-----------------------------\\\\

\begin{cases}
63=(r+2)t\implies \cfrac{63}{r+2}=\boxed{t}\\\\
51=(r-2)t\\
----------\\
51=(r-2)\left( \boxed{\cfrac{63}{r+2}} \right)
\end{cases}

solve for "r"
8 0
3 years ago
Whats the answer for (-6p+7)*-4
Vinvika [58]
The answer is -4. your welcome.

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3 years ago
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