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brilliants [131]

3 years ago

9

Grayson has 3 music lessons each week. Each lesson is 45 minutes long. How many total hours will he spend in music lessons in a

year

1 answer:

Anna [14]3 years ago

6 0

about 117 hours bc there are about 52 weeks in a year. And one week of 3 lessons is 2 (1/4)hrs. And 2(1/4) × 52 = 117 hrs

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Based on historical data in Oxnard college, we believe that 37% of freshmen do not visit their counselors regularly. For this ye

slega [8]

Answer:

A sample size of 1031 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is of:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

37% of freshmen do not visit their counselors regularly.

This means that $\pi = 0.37$

98% confidence level

So $\alpha = 0.02$ , z is the value of Z that has a pvalue of $1 - \frac{0.02}{2} = 0.99$ , so $Z = 2.327$ .

You would like to be 98% confident that your estimate is within 3.5% of the true population proportion. How large of a sample size is required?

A sample size of n is required.

n is found when M = 0.035. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.035 = 2.327\sqrt{\frac{0.37*0.63}{n}}$

$0.035\sqrt{n} = 2.327\sqrt{0.37*0.63}$

$\sqrt{n} = \frac{2.327\sqrt{0.37*0.63}}{0.035}$

$(\sqrt{n})^2 = (\frac{2.327\sqrt{0.37*0.63}}{0.035})^2$

$n = 1030.4$

Rounding up:

A sample size of 1031 is required.

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mixas84 [53]

Answer:c

Step-by-step explanation:

hyp=6 $\sqrt{2}$

adj=6

hyp:adj=6 $\sqrt{2}$ :2

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$=\frac{\sqrt{2} }{1} \\hyp:adj=\sqrt{2} :1$

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lesantik [10]

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