Hello,
h(x)'=(f(x)*g(x))'=f'(x)*g(x)+f(x)*g'(x)
h(1)=f'(1)*g(1)+(f(1)*g'(1)=-4*3+4*(-3)=-24
Answer B
Answer:
Step-by-step explanation:
2y = -x +9
3x - 6y = -15
The solution is the value of x and y that will make the two equations true in the same time.
3x-6y = -15; divide both sides by 3
x-2y = -5; substitute 2y for -x+9 because the first equation tell us they are equal
x-(-x+9) = -5; open parenthesis
x+x-9 = -5 ; add 9 to both sides and combine like terms
2x = -5 +9; 2x = 4; divide both sides by 2
x= 2
Substitute x for 2
2y = -x+9 ; 2y = -2 +9 ; 2y = 7; y = 7/2 = 3.5
Solution is (2, 3.5)
Answer:
<em>Rob has saved </em><em>$24</em><em>.</em>
Step-by-step explanation:
The first thing I noticed was that Rob only saved some of the money he earned. That means only x% only gets saved. To find x, I simply divided 6 by 14 and got 0.42857142857. Then to find the amount he saved from earning $56, I multiplied that number with 56 and got 24.
