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Xelga [282]
2 years ago
5

Which system of inequalities is represented by the graph?

Mathematics
1 answer:
asambeis [7]2 years ago
8 0

The system of inequalities that is represented by the graph is option b:  {y≥1y−x>0.

What is the inequalities  about?

The term inequality  is seen in mathematics as a kind of a statement that connote an order  type of relationship and it ranges from greater than, greater than or equal to and others.

Note that  The shaded area is said to be below the solid line at y=1, so the outcome of the set is said to be partially set up by the inequality .

Hence;

y≥1. . . . . . values of y in the solution set are greater than or equal to 1

The shaded area is seen below the line y=x, so is said to be partially determined by   y−x>0.

Learn more about inequalities from

brainly.com/question/17195738

#SPJ1

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drek231 [11]
To solve this problem you need to do a proportion. First you do 15 over x= 75 over 100. Now you multiply 15 by 100 which is 1500. Next, you divide 1500 by 75. YOUR ANSWER IS 20 peaches. To check your work, you could divide 20 by 4 which is 5. 5 times 3= 15 peaches.
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Brut [27]

Answer:

I believe it is C

Step-by-step explanation:

Sorry if I got it wrong but hopefully you got it right

6 0
3 years ago
What is an equation of the line that passes through the points (-6, -2) and
den301095 [7]

Answer:

The equation of line is: \mathbf{4x-3y=-18}

Step-by-step explanation:

We need to find an equation of the line that passes through the points (-6, -2) and  (-3, 2)?

The equation of line in slope-intercept form is: y=mx+b

where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding Slope

Slope can be found using formula: Slope=\frac{y_2-y_1}{x_2-x_1}

We have x_1=-6,y_1=-2, x_2=-3, y_2=2

Putting values and finding slope

Slope=\frac{2-(-2)}{-3-(-6)}\\Slope=\frac{2+2}{-3+6} \\Slope=\frac{4}{3}

So, we get slope: m=\frac{4}{3}

Finding y-intercept

Using point (-6,-2) and slope m=\frac{4}{3} we can find y-intercept

y=mx+b\\-2=\frac{4}{3}(-6)+b\\-2=4(-2)+b\\-2=-8+b\\b=-2+8\\b=6

So, we get y-intercept b= 6

Equation of required line

The equation of required line having slope m=\frac{4}{3} and y-intercept b = 6 is

y=mx+b\\y=\frac{4}{3}x+6

Now transforming in fully reduced form:

y=\frac{4x+6*3}{3} \\y=\frac{4x+18}{3} \\3y=4x+18\\4x-3y=-18

So, the equation of line is: \mathbf{4x-3y=-18}

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3 years ago
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