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scoundrel [369]
3 years ago
12

Um i need help on this lol

Mathematics
2 answers:
Kisachek [45]3 years ago
4 0

Answer:

um on what?

Step-by-step explanation:

⭐❤.☺☺☺☺☺the for the points ☺☺☺☺☺❤⭐

maksim [4K]3 years ago
3 0
I don’t see the question but thanks for the free points
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Show how you got the answer
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3 years ago
Find the expected value of the winnings from a game that has the following payout probability distribution: Skip Payout ($) 1 2
Nezavi [6.7K]

Answer:

$4.35

Step-by-step explanation:

The expected value of a random variable <em>X</em>, often denoted as E(<em>X</em>), indicates the probability-weighted average of all possible values/events. The general formula of expected value is

\mathrm{E(\textit X \mathrm)} = \displaystyle\sum_{\mathclap{i=1}}^{k} \ X \times P(X) \\ \\ \\ = X_{1} \times P(X_{1}) \ + \ X_{2} \times P(X_{2}) \ + \ X_{3} \times P(X_{3}) + \ \cdots \ + X_{k} \times P(X_{k}).

Therefore, the expected value of the winnings from a game is

\mathrm{E(\textit X \mathrm)} \ = \ 1 \times 0.35 \ + \ 2 \times 0.2 \ + \ 5 \times 0.1 + \ 8 \times 0.2 \ + 10 \times 0.15 \\ \\ = \ 4.35 \ \ (\mathrm{nearest \ hundredth}).

4 0
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