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Licemer1 [7]
2 years ago
7

if the lesser of two consecutive even integers is seven more than half the greater, what are the two integers?

Mathematics
1 answer:
beks73 [17]2 years ago
7 0

Answer: 16 and 18

Step-by-step explanation:

Let the lesser of two consecutive even integers is x.

Hence, the bigger of two consecutive even integers is (x+2).

\displaystyle\\x-\frac{x+2}{2}=7 \\

Multiply both parts of the equation by 2:

x(2)-(x+2)=7(2)\\2x-x-2=14\\x-2=14\\x-2+2=14+2\\x=16\\x+2=16+2\\x+2=18

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2x + 3y = 3 and x + 6y = -3
jekas [21]

Answer:

Step-by-step explanation:

Multiplying x+6y=-3 with 2 so its equal to first eqn,

Eliminating,

2x + 3y = 3        (1)

2x +12y = -6       (2)                  (because subtracting)

------------------

      -9y =9

     ∴y=-1

eq. y in 1

2x -3=3

2x=3+3

x=6/2

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4 0
3 years ago
Carlos has six cards in a bag, numbered 2, 2, 3, 6, 8, and 9. What is the probability Carlos will randomly select a 2 or a 9
AfilCa [17]

Answer:

50 percent

Step-by-step explanation:

100 percent divided by 6 (the amount of data) is 16 2/3.

Each number represents 16 2/3 percent.

3 of the numbers are either 2 or 9.

16 2/3x3=50.001

The final answer is a 50% probability.

<u>I think</u>

8 0
3 years ago
What’s the exact volume?
MAXImum [283]

I think the answer is option 3.

8 0
3 years ago
Read 2 more answers
Let A = {1, 2, 3, 4, 5} and B = {2, 4}. What is A ∩ B? (1 point)
katen-ka-za [31]

Answer:

{2, 4}.

Step-by-step explanation:

A = {1, 2, 3, 4, 5} and B = {2, 4}.

A ∩ B?

This means intersection or what is in common

A ∩ B =  {2, 4}.

8 0
3 years ago
(x^(2)-11x+30)/(x^(2)-25)*(x^(2)+6x+5)/(x-5x-6) simplify the rational expression
DanielleElmas [232]
Simplify the following:
((x^2 - 11 x + 30) (x^2 + 6 x + 5))/((x^2 - 25) (x - 5 x - 6))

The factors of 5 that sum to 6 are 5 and 1. So, x^2 + 6 x + 5 = (x + 5) (x + 1):
((x + 5) (x + 1) (x^2 - 11 x + 30))/((x^2 - 25) (x - 5 x - 6))

The factors of 30 that sum to -11 are -5 and -6. So, x^2 - 11 x + 30 = (x - 5) (x - 6):
((x - 5) (x - 6) (x + 5) (x + 1))/((x^2 - 25) (x - 5 x - 6))

x - 5 x = -4 x:
((x - 5) (x - 6) (x + 5) (x + 1))/((x^2 - 25) (-4 x - 6))

Factor -2 out of -4 x - 6:
((x - 5) (x - 6) (x + 5) (x + 1))/(-2 (2 x + 3) (x^2 - 25))

x^2 - 25 = x^2 - 5^2:
((x - 5) (x - 6) (x + 5) (x + 1))/(-2 (x^2 - 5^2) (2 x + 3))

Factor the difference of two squares. x^2 - 5^2 = (x - 5) (x + 5):
((x - 5) (x - 6) (x + 5) (x + 1))/(-2(x - 5) (x + 5) (2 x + 3))

((x - 5) (x - 6) (x + 5) (x + 1))/((x - 5) (x + 5) (-2) (2 x + 3)) = ((x - 5) (x + 5))/((x - 5) (x + 5))×((x - 6) (x + 1))/(-2 (2 x + 3)) = ((x - 6) (x + 1))/(-2 (2 x + 3)):
((x - 6) (x + 1))/(-2 (2 x + 3))

Multiply numerator and denominator of ((x - 6) (x + 1))/(-2 (2 x + 3)) by -1:

Answer: (-(x - 6) (x + 1))/(2 (2 x + 3))
4 0
3 years ago
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