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Licemer1 [7]
1 year ago
7

if the lesser of two consecutive even integers is seven more than half the greater, what are the two integers?

Mathematics
1 answer:
beks73 [17]1 year ago
7 0

Answer: 16 and 18

Step-by-step explanation:

Let the lesser of two consecutive even integers is x.

Hence, the bigger of two consecutive even integers is (x+2).

\displaystyle\\x-\frac{x+2}{2}=7 \\

Multiply both parts of the equation by 2:

x(2)-(x+2)=7(2)\\2x-x-2=14\\x-2=14\\x-2+2=14+2\\x=16\\x+2=16+2\\x+2=18

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Answer:

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Step-by-step explanation:

step 1

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Remember that

Everything to the left of the solid line is shaded

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step 2

<em>Find the equation of the second inequality</em>

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substitute

y=-\frac{1}{2}x+2

Remember that

Everything below and to the left of the line is shaded

so

The inequality is

y

Rewrite

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The system of inequalities is

y\geq x-2

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see the attached figure to better understand the problem

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1992.1875
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Ok I don't know waht you mean but the answer is

Step-by-step explanation:

Answer:

x=3/2±(√11)2

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