Let 
be the number of students who eat cauliflower.
Therefore, 
.
Let 
be the total number of students surveyed.
Therefore, 
Thus, 
Now, for 90% confidence level, from the table we know that 
.
The formula for the interval range of proportion of students is :
Plugging in the values we get:
Thus, Jane is 90% confident that the population proportion p, for students who eat cauliflower in her campus is between 5.398% and 15.114% (after converting the answer we got to percentage).
Answer:
-7
Step-by-step explanation:
-2 + 3v = -23 >> -2 + 23 = -3v >> 21 = -3v >> v = -7
It has to do with the unit circle, I think it is A because it should be 2(0+ (-1)) but I would probably wait for someone to come behind me and explain it better sorry couldn't help more
(A) For x representing the cost of one of Tanya's items, her total purchase cost 5x. The cost of one of Tony's items is then (x-1.75) and the total of Tony's purchase is 6(x-1.75). The problem statement tells us these are equal values. Your equation is ...
... 5x = 6(x -1.75)
(B) Subtract 5x, simplify and add the opposite of the constant.
... 5x -5x = 6x -6·1.75 -5x
... 0 = x -10.50
... 10.50 = x
(C) 5x = 5·10.50 = 52.50
... 6(x -1.75) = 6·8.75 = 52.50 . . . . . the two purchases are the same value
(D) The individual cost of Tanya's iterms was $10.50. The individual cost of Tony's items was $8.75.
