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Sergio039 [100]
2 years ago
7

Please, please please help!!! my assignment is due today and i need help.

Mathematics
1 answer:
OlgaM077 [116]2 years ago
6 0
Can you post a picture so its better to understand
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How much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 40% antifreeze
nexus9112 [7]

Let the necessary amount of water be x.  Then (1.00)(1 gallon antifreeze) = 0.40(x+1 gallon), or 1 = .40x + .40.  Combining like terms:  0.60 = 0.40x.

Then x = 0.60 / 0.40 = 1.5.

Adding 1.5 gallons of water to that 1 gallon of pure antifreeze results in 2.5 gallons of 40% antifreeze.

6 0
3 years ago
Determine whether the point (2, 0) is a solution to the system of equations. Explain your reasoning in complete sentences. graph
DochEvi [55]

Hello Ebjune,


Your answer would be:

The point of intersection of the graphs of the given equation is (0, 2). Therefore, point (1, 1) This not a solution!


Hope this helps!


Brainliest!?!


Have a great day:)


~Rendorforestmusic

7 0
3 years ago
Read 2 more answers
If q(x)=7x^2-1 ; find Q(-10)
maksim [4K]
In terms of PEMDAS, you would first find -10 squared, which is 100, and multiply it by 7, giving you 700-1. The answer would be 699.

If you weren't going by PEMDAS, then you would take 7, multiply it by -10, square that, and subtract one from it. -70^2=4,900. Subtract 1, and your answer is 4,899.
8 0
3 years ago
Chocolate shake takes 8/9 pint of milk . If the medium takes 1/7 the amount of large , how much does the medium take ??
aivan3 [116]
\frac{8}{9}-large\ shake\\\\ Medium\ shake:\\\frac{1}{7}\cdot \frac{8}{9}= \frac{8}{63}\\\\Medium\ shake\ takes\ \frac{8}{63}\ pint\ of\ milk.
3 0
3 years ago
What is the equation of the line which includes points HELP ASAP
Harman [31]

Answer:

OPTION C

OPTION A

OPTION C

Step-by-step explanation:

We use two - point form to determine the equation of the line when two points are given.

The two - point form is: $ \frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1} $, where $ (x_1, y_1) $ and $ (x_2, y_2) $ are the two points passing through it.

1) (x₁, y₁) = (2, 3) and (x₂, y₂) = (0, 10)

Using the two - point form, we have:

$ \frac{y - 3}{10 - 3} = \frac{x - 2}{0 - 2} $

$ \frac{y - 3}{7} = \frac{x -2}{-2} $

$ \implies - 2y + 6 = 7x - 14 $

$ \implies 7x - 20 = - 2y $

Dividing by -2, we get:

$ y = - \frac{7}{2}x + 10 $ is the equation of the line.

2) (x₁, y₁) = (1, 1) and (x₂, y₂) = (1, 5)

Using the slope - point form, we get:

$ \frac{y - 1}{5 - 1} = \frac{x - 1}{1 - 1} $

$ \implies \frac{y - 1}{5 - 1} = \frac{x - 1}{0} $

$ 0 = x - 1 $

⇒ x = 1 is the required equation of the line.

3) (x₁, y₁) = (-5, 5) and (x₂, y₂) = (2, 5)

Using the slope - point form, we get:

$ \frac{y - 5}{5 - 5} = \frac{x + 5}{2 - 5} $

$ \implies \frac{y - 5}{0} = \frac{x + 5}{-3} $

$ \implies y - 5 = 0 $

⇒ y = 5 is the required equation of the line.

3 0
3 years ago
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