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sergij07 [2.7K]
2 years ago
6

Pls help gsoehehsjbsgshsjbsfeoanevshksnevehwknsbdgsknwbsgdindvegshsn

Mathematics
1 answer:
Kryger [21]2 years ago
4 0

Answer:

a)  5.9

b)  4.2

Step-by-step explanation:

Plot the data points on the number line (see attached).

<u>Part (a)</u>

\begin{aligned}\textsf{Distance between Ben and Kloee} & = \sf \left| Ben - Kloee \right|\\& = \sf \left|-2.65-3\frac{1}{4}\right|\\& = \sf \left|-2.65-3.25\right|\\& = \sf \left|-5.9\right|\\& = \sf 5.9\end{aligned}

<u>Part (b)</u>

\begin{aligned}\textsf{Distance between Middle school and Football field} & = \sf \left| Middle\:school-Football\:field\right|\\& = \sf \left| 1.5-5.7\right|\\& = \sf \left| -4.2 \right|\\& = \sf 4.2\end{aligned}

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➷ First, just divide the numbers:

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\text{the three consecutive terms in an arithmetic sequence}\\a;\ a+d;\ a+2d\\\\\text{system of equals}\\\\ \left\{\begin{array}{ccc}a+a+d+a+2d=27\\a(a+d)(a+2d)=585\end{array}\right\\ \left\{\begin{array}{ccc}3a+3d=27&|:3\\a(a+d)(a+2d)=585\end{array}\right\\ \left\{\begin{array}{ccc}a+d=9&\to d=9-a\\a(a+d)(a+2d)=585\end{array}\right\\
\text{substitute to the second equation}\\\\a(a+9-a)(a+2(9-a))=585\\\\a(9)(a+18-2a)=585\\9a(18-a)=585\ \ \ |:9\\a(18-a)=65\\18a-a^2=65\ \ \ |\text{change the signs}\\a^2-18a=-65\\a^2-2a\cdot9=-65\ \ \ |+9^2\\\underbrace{a^2-2a\cdot9+9^2}_{(a-b)^2=a^2-2ab+b^2}=-65+9^2\\(a-9)^2=16\to a-9\pm\sqrt{16}\\a-9=-4\ \vee\ a-9=4\ \ \ |+9\\a=5\ \vee\ a=13\\\\d=9-5=4\ \vee\ d=9-13=-4
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In trapezoid RTUW, V is the midpoint of segment UW, and S is the midpoint of segment RT. Find UT.
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