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Zepler [3.9K]
3 years ago
7

Least common multiple of 6 and 8

Mathematics
2 answers:
kicyunya [14]3 years ago
7 0

\huge\text{Hey there!}


\large\textsf{What are the least common multiples of 6 and 8?}


\large\textsf{Well, first lets find the multiples of both of the numbers \& see}\\\large\textsf{what we could find.}


\huge\textbf{The MULTIPLES of 6}\\\bullet\large\text{ 6, 12, 18,24, 30, and 36}

\huge\textbf{The MULTIPLES of 8}\\\bullet\large\text{ 8, 16, 24, 32, and 40}

\large\textsf{Each of the numbers listed above shared ONE number \& it is 24}

\huge\text{Answer: \boxed{\mathsf{\bold{L}owest \ \bold{C}ommon \ \bold{M}ultiple: 24}}}\huge\checkmark


\huge\text{Good luck on your assignment \& enjoy your day!}


~\frak{Amphitrite1040:)}

miskamm [114]3 years ago
3 0

Answer:

8={8,16,24,32,40}

6={6,12,18,24,33}

so the least common multiple is 24

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Given AG bisects CD, IJ bisects CE, and BH bisects ED. Prove KE = FD.
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When a line is bisected, the line is divided into equal halves.

See below for the proof of \mathbf{KE \cong FD}

The given parameters are:

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<em />

By definition of segment bisection, we have:

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By definition of congruent segments, the above congruence equations become:

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By segment addition postulate, we have:

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Substitute \mathbf{ED = EF + FD} in \mathbf{CE = ED}

\mathbf{CK + KE = EF + FD}

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Read more about proofs of congruent segments at:

brainly.com/question/11494126

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