Answer/Step-by-step explanation:
H = V/lw
H = 984/20.5*6
H = 984/128
H = 8
<em><u>ANSWER:</u></em>
<em><u>H = 8</u></em>
Step-by-step explanation:
Answer:
27 ft
the maximum height of the arrow is 27 ft
Step-by-step explanation:
Given;
The height of the arrow is given by the function;
h(t) = -16t^2 + 32t + 11
Maximum height is at point when dh(t)/dt = 0.
Differentiating h(t), we have;
dh/dt = -32t + 32 = 0
Solving for t;
-32t = -32
t = -32/-32 = 1
t = 1 (time at maximum height is t = 1)
Substituting t=1 into h(t), to determine the value of maximum height;
h(max)= -16(1^2) + 32(1) + 11
h(max) = 27 ft
the maximum height of the arrow is 27 ft.
Answer:
The answer is D
Step-by-step explanation:
Answer:
P=a+b+c
Step-by-step explanation:
a=side
b=base
c=side
in your case do this for each two lines on every angle and use base for the shape inside hope this helps
