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3 years ago

1. (10 points) Explain how to factor the following:

Mathematics

1 answer:

kap26 [50]3 years ago

6 0

Answer:

A. 3m² + 4m + 1 = 0

3m² + 3m + m + 1 = 0

3m (m + 1) + 1 (m + 1) = 0

( 3m + 1 ) (m + 1) = 0

B. 16n - 25

16n = 25

n = 25/16

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3 years ago

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Please work out and explain

Mekhanik [1.2K]

Answer:

a = 22

b = 31

c = 13

Step-by-step explanation:

The sum is the same in each row, column, and diagonal.

One of the diagonals is already complete. The sum is:

16 + 25 + 34 = 75

So the first row adds up to 75:

a + 37 + 16 = 75

a = 22

The second row adds up to 75:

19 + 25 + b = 75

b = 31

And the third row adds up to 75:

34 + c + 28 = 75

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We can check our answer by finding the sum of each column and the other diagonal.

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3 years ago

The Copy Shop has made 20 copies of a document for you. Since the defective rate is 0.1, you think there may be some defective c

Pepsi [2]

Answer:

Binomial

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

Step-by-step explanation:

For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinatios of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem

Of the 20 copies, 2 are defective, so $p = \frac{2}{20} = 0.1$ .

What is the probability that you will encounter neither of the defective copies among the 10 you examine?

This is P(X = 0) when $n = 10$ .

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

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