Answer:
410
Step-by-step explanation:
i dont understand exactly
Answer:
The answer is 14.5
Step-by-step explanation:
Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
The 2 triangles are congruent
Answer:
$130
Step-by-step explanation:
Because you multiple 3 and 10 to get 30 and 5 and 20 to get 100 and then add 100+30 to get 130 and that would be 130 dollars in one day
