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ivolga24 [154]
3 years ago
15

600 is the value of what number

Mathematics
2 answers:
Digiron [165]3 years ago
4 0

Answer: Hundreds

Step-by-step explanation:

dalvyx [7]3 years ago
4 0
It’s the hundreds place hope this helps:)
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A satellite can move at 17,000 miles per hour. how many hours will it take to reach a star that is three light years away? recal
Feliz [49]
Distance to the star in light years = 3 * 0.62 * 9.5 * 10^12  =  1.767 * 10^13 miles

dividng this by 17,000  gives  1.039411765 * 10^9 hours
7 0
4 years ago
the length of a rectangle is 3 cm less than the width. the area is 54cm^2. what is the length and the width of the rectangle?
GrogVix [38]

Answer:

The length of the rectangle is 6cm while the width is 9cm

Step-by-step explanation:

Here, we are interested in calculating the length and width of the rectangle.

Let the length of the rectangle be x cm

We are told that the length is 3 cm

less than the width, this means that the width is (x + 3) cm

The area of the rectangle is 54cm^2

Mathematically;

Area of rectangle = L * B

Thus;

x(x + 3) = 54

x^2 + 3x = 54

x^2 + 3x -54 = 0

x^2 + 9x -6x -54 = 0

x(x + 9 ) -6(x + 9) = 0

(x -6)(x + 9) = 0

x -6 = 0 or x+ 9 = 0

x = 6 or -9

Since length cannot be negative we choose x = 6cm

But width = x + 3 = 6 + 3 = 9cm

6 0
3 years ago
4 mi = ft. help fast please
Afina-wow [57]
5280 per mile ! 21120! Good luck!
4 0
3 years ago
Read 2 more answers
I need help with a math question please?
elena55 [62]
To find the tan x use the following formula
tan x = (sin x)/(cos x)
tan x = (1/2)/(sqrt (3)/2)
tan x = 1/sqrt (3) = sqrt (3)/3 or E
6 0
4 years ago
Find the arc length of the following curve on the given interval. x equals 12 t minus 5 comma y equals 16 t plus 3 ​, 0 less tha
Kipish [7]

Answer:

80

Step-by-step explanation:

We are given:

x(t) = 12t-5\\y(t) = 16t+3\\0\leq t\leq4 ⇒ [\alpha,\beta] = [0,4]

To find arc length, we will use the following formula,

\int\limits^\beta_\alpha\sqrt{(\frac{dx}{dt})^2+\frac{dy}{dt})^2}\:dt=\int\limits^4_0\sqrt{12^2+16^2}\:dt=20t|^4_0 = 20*(4-0)=80

6 0
4 years ago
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