Question

Use the given frequency distribution to find the class width, class midpoint, and class boundaries​

Answer 1

Based on the table attached, the class boundaries are as follows: 43.5, 49.5, 53.5, 59.5, 63.5, 69.5, 73.5, 79.5.

What is the frequency distribution about?

Temperature (°F) Frequency

40-44 1

45-49 3

50-54 5

55-59 11

60-64 7

65-69 7

70-74 1

A. Viewing at the frequency table, we find that the lower class limits of two consecutive classes are 40 and 44, respectively. Thus the class width is:

 Class width = 44 − 40= 4

B: One can find the class midpoints by putting the average of the lower and upper class limits. So the midpoint of the first class is  seen below:

=  40  - 44 = $\frac{40 + 44}{2}$   = 42. In a similar way, we find the rest.

C. The Class boundaries is known to be that which separate the classes removing the class limits. The class boundaries are as follows:

43.5, 49.5, 53.5, 59.5, 63.5, 69.5, 73.5, 79.5

Therefore, Based on the table attached, the class boundaries are as follows: 43.5, 49.5, 53.5, 59.5, 63.5, 69.5, 73.5, 79.5.

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