Question

Find the 12th term of the geometric sequence 1, -4, 16,

Answer 1

Answer:

a₁₂ = - 4194304

Step-by-step explanation:

the nth term of a geometric sequence is

$a_{n}$ = a₁ $(r)^{n-1}$

where a₁ is the first term and r the common ratio

here a₁ = 1 and r = $\frac{-4}{1}$ = - 4 , then

a₁₂ = 1 × $(-4)^{11}$ = - 4194304