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2 years ago

Find the 12th term of the geometric sequence 1, -4, 16,

Mathematics

1 answer:

Korvikt [17]2 years ago

8 0

Answer:

a₁₂ = - 4194304

Step-by-step explanation:

the nth term of a geometric sequence is

$a_{n}$ = a₁ $(r)^{n-1}$

where a₁ is the first term and r the common ratio

here a₁ = 1 and r = $\frac{-4}{1}$ = - 4 , then

a₁₂ = 1 × $(-4)^{11}$ = - 4194304

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Simply<br> (2k-9)^2+(k+2)^2=(2k+1)^2+(k-8)^2

vova2212 [387]

The square of a binomial expands as follows:

$(a+b)^2=a^2+2ab+b^2$

Expanding all the binomials, we have

$4k^2-36k+81+k^2+4k+4=4k^2+4k+1+k^2-16k+64$

Sum like terms:

$5k^2-32k+85=5k^2-12k+65$

Simplify terms appearing on both sides:

$-32k+85=-12k+65$

Move all terms involving k to the left and all numbers to the right:

$-20k=-20$

Divide both sides by -20:

$k=1$

6 0

3 years ago

The diagram shows a logo

Charra [1.4K]

Answer/Step-by-step explanation:

✔️Find EC using Cosine Rule:

EC² = DC² + DE² - 2*DC*DE*cos(D)

EC² = 27² + 14² - 2*27*14*cos(32)

EC² = 925 - 756*cos(32)

EC² = 283.875639

EC = √283.875639

EC = 16.85 cm

✔️Find the area of ∆DCE:

Area = ½*14*27*sin(32)

Area of ∆DCE = 100.15 cm²

✔️Since ∆DCE and ∆ABE are congruent, therefore,

Area of ∆ABE = 100.15 cm²

✔️Find the area of the sector:

Area of sector = 105/360*π*16.85²

Area = 260.16 cm² (nearest tenth)

✔️Therefore,

Area of the logo = 100.15 + 100.15 + 260.16 = 460.46 ≈ 460 cm² (to 2 S.F)

5 0

3 years ago

6×5/6=24 I think I hope

Rom4ik [11]

No 6x5/6 is 5.
6x5 is 30.
30/6=5
Ignore @popmypussy
Hope i could help!
Thunderclan89

7 0

3 years ago

Jack plays on a basketball team after school third day of the month he babysits every seventh day of the month how many times du

Alex787 [66]

Great question!
If you draw a calendar see attachment for mine.you will see that the dates for Basketball are
3,6,9,12,15,18,21,24,27,30
and the dates for Babysitting are
7,14,21,28

There would only be a conflict on the 21st! So the answer is 1 time!

4 0

3 years ago

Which statement is true?

julsineya [31]

Answer:

answer is <u>option A </u>

Step-by-step explanation:

Sure hope this helps uou :)

8 0

2 years ago