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3 years ago

Determine the direction that is parabola opens: y = -5x^2 -10x -13

Mathematics

1 answer:

Lunna [17]3 years ago

8 0

The parabola opens down, since the 'a' value of the equation is a negative value.

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Roman55 [17]

Anser: Brooo

Step-by-step explanation:

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8 0

2 years ago

A retailer returned 2,124 defective items to the manufacturer and received a credit for the retail price of $0.66 or 66

gregori [183]

Answer:

the answer is 2279.35

Step-by-step explanation:

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3 0

3 years ago

Determine the equation of the circle graphed below. ( please help me )

Brums [2.3K]

Answer:

$Equation : \\(x+3)^2 + ( y -2)^2 = 36$

Step-by-step explanation:

For standard form the circle's equation we need the centre of the circle and the radius.

Step 1: Find the centre

If the centre is not given find the end points of the diameter

and then find the mid point.

Let the end points of the diameter be : ( - 3 , 8 ) and ( -3 , -4 )

The mid-point of the diameter is :

$Mid-point = (\frac{-3 + - 3}{2}, \frac{-4+8}{2}) = (-3, 2)$

Therefore, centre of the circle = ( -3 , 2 )

Step 2 : Find radius

$Radius = \frac{Diameter }{2}$

Diameter is the distance between the end points ( -3 , 8) and ( -3 , -4 )

That is ,

$Diameter = \sqrt{(-3-(-3))^2 + ( -4 -8)^2}\\$

$= \sqrt{(-3 + 3)^2 + (-12)^2}\\\\=\sqrt{0 + 144}\\\\=12$

Therefore ,

$Radius = \frac{12}{2} = 6$

Step 3 : Equation of the circle

Standard equation of the circle with centre ( h ,k )

and radius ,r is :

$(x - h)^2+(y -k)^2 = r^2$

Therefore, the equation of the circle with centre ( -3, 2)

and radius = 6 is :

$(x - (-3))^2 + (y - 2)^2 = 6^2\\\\(x + 3)^2 + (y - 2)^2 = 36$

5 0

2 years ago

What is NOT true about a direct proportion

SVEN [57.7K]

It’s graph must go through the origin ?

5 0

3 years ago

3. Find the slope of the line that goes through the following points: (6.-1) and (-3, 11)

Alik [6]

Answer:

1.33

Step-by-step explanation:

y2-y1/x2-x1

=11+1/-3-6

=12/-9

=-4/3

=1.33

3 0

3 years ago