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2 years ago

14

A safety regulation states that the minimum height of a handrail is 30 inches. The maximum height is 38 inches. Write an absolut

e value equation that represents the minimum and maximum heights.

1 answer:

atroni [7]2 years ago

3 0

Answer:

Step-by-step explanation:

Minimum height=30

Maximum height=38

Write an absolute value equation:

Center: 34

Distance: 4

Equation: |x-34|=4

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Simplify each expression justify each step 6+(8x +13)

zhuklara [117]

That's easy you just need to listen in school to answer it

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2 years ago

Khalid carried water bottles to the field to share with his team at halftime. The water bottles weighed

jeka57 [31]

Answer:

<u>Answer</u><u>:</u><u> </u><u>D</u>

${50x}^{2} + 30x + 10$

• first factorise out 10:

$= 10(5 {x}^{2} + 3x + 1)$

• then find factors of the quadratic equation in the bracket:

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2 years ago

Simplify 4+(9×2)÷(4-2)+1

kogti [31]

First we have to work out everything inside the parentheses (according to PEMDAS):

9 × 2 = 18

4 - 2 = 2

Now, we can rewrite the expression:

4 + 18 ÷ 2 + 1

According to PEMDAS, we should complete the division in the middle first:

18 ÷ 2 = 9

Now we can rewrite the expression again:

4 + 9 + 1

And now it's as simple as just adding the three numbers together:

4 + 9 + 1 = 14

Your final answer is 14. :)

3 0

2 years ago

Read 2 more answers

FIRST TO ANSWER GETS BRAINLIEST!

scZoUnD [109]

Answer:

$\huge \boxed{ \red{ \boxed{c)78 \: units ^{2} }}}$

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>

circle
PEMDAS

<h3>tips and formulas:</h3>

$\rm \:A_{shaded}= \dfrac{\theta}{360} \times \pi {r}^{2}$

<h3>let's solve:</h3>

$\sf sustitute \: the \: value \: of \: \theta \: and \: r : \\ A_{shaded} = \frac{140}{360} \times \pi \times {8}^{2}$
$\sf simpify \: squre : \\ A_{shaded} = \frac{140}{360} \times \pi \times 64$
$\sf simpify \: fraction: \\ A_{shaded} = \frac{7}{18} \times \pi \times 64$
$\sf reduce \: 64: \\ A_{shaded} = \frac{7}{ \cancel{ \: 18} \: ^{9} } \times \pi \times \cancel{ 64} \: ^{32} \\ A_{shaded} = \frac{7}{9} \times \pi \times 32\\ A_{shaded} = \frac{224\pi}{9}$

$\large A_{shaded}\approx 78 \: square \: units$

8 0

2 years ago

Read 2 more answers

Adult female height is normally distributed with a mean of 65.3 inches and a standard deviation of 2.32 inches. a) If an adult f

emmasim [6.3K]

Answer:

0.0423 is the probability that the adult female has a height less than 61.3 inches.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 65.3 inches

Standard Deviation, σ = 2.32 inches

We are given that the distribution of adult female height is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(adult female has a height less than 61.3 inches)

$P( x < 61.3) = P( z < \displaystyle\frac{61.3 - 65.3}{2.32}) = P(z < -1.7241)$

Calculation the value from standard normal z table, we have,

$P(x < 61.3) =0.0423 = 4.23\%$

0.0423 is the probability that the adult female has a height less than 61.3 inches.

5 0

3 years ago