Answer:
B
Step-by-step explanation:
because the angles 1 and 7 are alternate and equal , we can conclude that p and q are parralel
Answer:
Step-by-step explanation:
So A = the child is 5-10 years old and B = the child is 11-13 years of age and that covers all the children in the study. I = calcium intake is inadequate.
Use the rules of logarithms and the rules of exponents.
... ln(ab) = ln(a) + ln(b)
... e^ln(a) = a
... (a^b)·(a^c) = a^(b+c)
_____
1) Use the second rule and take the antilog.
... e^ln(x) = x = e^(5.6 + ln(7.5))
... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents
... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms
... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)
2) Similar to the previous problem, except base-10 logs are involved.
... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.
... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5
... x ≈ 53,080.96
Answer:
W = 76m
L = 83
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
The price p, in dollars, of a specific car that is x year old is modeled by the function p(x)=22,255(0.91)^x
a) to determine the cost of a 2 year old car, we will substitute 2 for x in the given function. Therefore
p(2)=22,255(0.91)^2
p(2)=22,255 × 0.8281 = $18673.655
Approximately $18674
b) to determine the cost of a 7 year old car, we will substitute 7 for x in the given function. Therefore
p(7)=22,255(0.91)^7
p(2)=22,255 × 0.51676101936 = 11500.51648579693
Approximately $11501
c) 0.91 indicates exponential decay rate. It is a fixed percentage by which the value of the car decreases every year. It is determined by (1 - rate of decay)
