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Anastasy [175]
3 years ago
9

What is measure of angle R?

Mathematics
1 answer:
Oliga [24]3 years ago
4 0
Angle R can be solved using the inverse sine button on a calculator. Sine is y/r so opposite leg over the hypotenuse. For r, the opposite leg is 5cm and the hypotenuse is 13. The inverse sin button looks like sin^-1. Punch that in the calculator (make sure in degree mode). Punch the inverse sin and then 5/13 and you should get 22.62°
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11 points Please answer quick.
ICE Princess25 [194]

Answer:

\boxed{x^4 + x^2 + x}

Step-by-step explanation:

\frac{x^5 - x^4 + x^3 -x^2 + x - 1}{x - 1}

= \frac{(x - 1)(x^4 + x^2 + x)}{x - 1}

= x^4 + x^2 + x

.

Happy to help :)

5 0
3 years ago
I don’t know how to do this please help please!!!
Irina18 [472]

Answer:

study more so you can understand

3 0
3 years ago
Solve. Show work please. Passing through (-3,-1) and (2,4)
melisa1 [442]

Slope formula: (y² - y¹) / (x² - x¹)

(-3, -1) (2, 4)

x¹ = -3

x² = 2

y¹ = -1

y² = 4

4 - (-1) = 5

2 - (-3) = 5

5/5 = 1

So the slope is 1.

Hope this Helps!!

6 0
3 years ago
Is anyone good at geometry if so can you help me please ?
Pachacha [2.7K]

The arcs FA, AB, and <u>BF</u> make up the entire circle, so their measures sum to 360°:

arcFA + arcAB + arcBF = 360°   →   arcBF = 360° - 160° - 140° = 60°

By the inscribed angle theorem, angle BAF has measure equal to half of that of arc BF, so

angleBAF = 30°

By the secant-tangent theorem (not sure if there's an official name for it), the measure of angle ACF is equal to half the difference of the arcs it intercepts, namely BF and FA, so that

angleACF = 1/2 (arcFA - arcBF) = 1/2 (160° - 60°) = 50°

Now use the law of sines for solve for FA:

sin(angleACF) / FA = sin(angleBAF) / FC

sin(50°) / FA = sin(30°) / 10

FA = 10 sin(50°) / sin(30°) ≈ 15.3

3 0
3 years ago
Paul travel to the lake and back. The trip took 3 hours and the trip back took 4 hours He averaged 10 mph faster on the trip the
ollegr [7]

Answer:

  40 mph

Step-by-step explanation:

We assume "outbound" refers to the trip <em>to the lake</em>. The ratio of speeds is inversely proportional to the ratio of times, so ...

  outbound speed : inbound speed = 4 : 3

These differ by one ratio unit, so that one ratio unit corresponds to the speed difference of 10 mph. Then the 4 ratio units of outbound speed will correspond to ...

  4×10 mph = 40 mph

Paul's average speed on the outbound trip was 40 mph.

___

The distance to the lake was 120 mi.

4 0
3 years ago
Read 2 more answers
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