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2 years ago

Graph a line with a slope of 2/5 that contains the ping (-2,4)

1 answer:

4 0

Hello there! A point that would verify the slope to be 2/5 would be (0, 9).

Given the point (-2,4) and the slope 2/5, we can follow the slope formula of rise/run, where 2 is our rise (y) and 5 is our run (x). Moving up two points on the y-axis will give us our rise, 0, because -2 + 2 = 0. Moving to the right 5 units from 4 on the x-axis will give us our run, 9, because 5 + 4 = 9.

Your final answer: One of the points on the graphed line will be (0,9). When progressing two points up and 5 points to the right, we will obtain more points. Hope this helps!

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Bill and Amy want to ride their bikes from their neighborhood to school which is 14.4 kilometers away. It takes Amy 40 minutes t

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3 years ago

Brad is having a party and buys a large cube of cheddar cheese at the market. The cube is 4 inches in height. When Brad gets hom

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3 years ago

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3 years ago

Read 2 more answers

What are the ordered pairs of the

9966 [12]

Start by writing the system down, I will use $y$ to represent $f(x)$

$y=x^2-5x+3\wedge y=-3$

Substitute the fact that $y=-3$ into the first equation to get,

$-3=x^2-5x+3$

Simplify into a quadratic form ( $ax^2+bx+c=0$ ),

$x^2-5x+6=0$

Now you can use Vieta's rule which states that any quadratic equation can be written in the following form,

$x^2+x(m+n)+mn=0$

which then must factor into

$(x+m)(x+n)=0$

And the solutions will be $m,n$ .

Clearly for small coefficients like ours $5,6$ , this is very easy to figure out. To get 5 and 6 we simply say that $m=3, n=2$ .

This fits the definition as $5=3+2$ and $6=2\cdot3$ .

So as mentioned, solutions will equal to $m=3, n=2$ but these are just x-values in the solution pairs of a form $(x,y)$ .

To get y-values we must substitute 3 for x in the original equation and then also 2 for x in the original equation. Luckily we already know that substituting either of the two numbers yields a zero.

So the solution pairs are $(2,0)$ and $(3,0)$ .

Hope this helps :)

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3 years ago