Answers:
- a) 15000 represents the starting amount
- b) The decay rate is 16%, which means the car loses 16% of its value each year.
- c) x is the number of years
- d) f(x) is the value of the car after x years have gone by
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Explanation:
We have the function f(x) = 15000(0.84)^x. If we plug in x = 0, then we get,
f(x) = 15000(0.84)^x
f(0) = 15000(0.84)^0
f(0) = 15000(1)
f(0) = 15000
In the third step, I used the idea that any nonzero value to the power of 0 is always 1. The rule is x^0 = 1 for any nonzero x.
So that's how we get the initial value of the car. The car started off at $15,000.
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The growth or decay rate depends entirely on the base of the exponential, which is 0.84; compare it to 1+r and we see that 1+r = 0.84 solves to r = -0.16 which converts to -16%. The negative indicates the value is going down each year. So we have 16% decay or the value is going down 16% per year.
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The value of x is the number of years. In the first section, x = 0 represented year 0 or the starting year. If x = 1, then one full year has passed by. For x = 2, we have two full years pass by, and so on.
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The value of f(x) is the value of the car after x years have gone by. We found that f(x) = 15000 when x = 0. In other words, at the start the car is worth $15,000. Plugging in other x values leads to other f(x) values. For example, if x = 2, then you should find that f(x) = 10584. This means the car is worth $10,584 after two years.
Answer:
The length of the segment AB is 18.8 cm or 1.88 dm
Step-by-step explanation:
<u><em>The question in English is</em></u>
Points A, B and C are collinear in this order. Find the length of the segment: a) AB, if AC = 20 cm, BC = 0.12 dm
we have that
----> by Addition segment postulate
substitute the given values in centimeters
Remember that
so
solve for AB
Convert to dm
therefore
The length of the segment AB is 18.8 cm or 1.88 dm
Answer:
part 1 : y = x^2 + 3x + 5
y = x + 13
solution:
x^2 + 3x + 5 = x + 13
x^2 + 2x -8 = 0
(x+4)(x-2) = 0
x = -4 or x = 2
if x = -4, y = 9
if x = 2 , y = 15
part 2 : x^2 + 2x + 1 = 0
(x + 1)^2 = 0
x = -1
y = 1
task 2
part 1 : Let our two digit number be 26
Next, we rewrite it as a difference of two numbers
26=32-6
We want to square 26 using the identity:
In this case,
x=32
y=6
Substituting into the identity
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Answer:
x=5
Step-by-step explanation:
Alright you will need to use PEMDAS for this
- Parenthesis
- Exponent
- Multiplication
- Division
- Addition
- Subtraction ( Take note of this )
Step 1
9(3x – 16) + 15 = 6x – 24 You will remove parenthesis here
27x-129=6x-24
Step 2
Then subtract 6x,
27x-129=6x-24
21x-129=-24
Step 3
Then you add 129 to the sides,
21x-129=-24
21x=105
After that, you divide the sides by 21 so that you can get your answer
5
So therefore, your answer will be x=5
