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arlik [135]
2 years ago
9

if the first and third of three consecutive odd integers are added, the result is 63 less than five times the second integer. fi

nd the third integer.
Mathematics
1 answer:
ollegr [7]2 years ago
5 0

The value of third consecutive odd is 23

• In Mathematics, algebra is a branch which only deals with symbols and the rule for  the manipulation of these symbols. Algebra is divided into different sub branches such as advanced algebra, linear algebra, elementary algebra, abstract algebra etc.

• The basics of algebra contains numbers, variables, constants, expressions and equations. The basic four operations of algebra are addition, subtraction, multiplication, division.

Let the first consecutive odd integer be x

Second consecutive integer = x+2

Third consecutive integer = x+4

We are given that

First + third = 5(Second) – 63

x + x + 4 = 5 (x+2) -63

2x + 4 = 5x +10 -63

-3x = -57

3x = 57

x = 19

First Consecutive odd = 19

Second Consecutive odd = 21

Third Consecutive odd = 23

Learn more about algebra here

brainly.com/question/723406

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3 years ago
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Зx +1 &lt;10<br> What is the answer for this
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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define Inequality</u>

3x + 1 < 10

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Subtract 1 on both sides:                    3x < 9
  2. Divide 3 on both sides:                       x < 3

Here we see that any value <em>x</em> smaller than 3 would work as a solution to the inequality.

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