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Tasya [4]
3 years ago
10

What is this problem

Mathematics
1 answer:
sergeinik [125]3 years ago
3 0

Answer:

m=A-\frac{2n}{Z}

Step-by-step explanation:

Multiply by 2:

2n = Z(A - m)

Divide by Z:

\frac{2n}{Z} =A-m

Subtract A:

-m=\frac{2n}{Z}-A

Multiply by -1:

m=A-\frac{2n}{Z}

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What is (2m+5) to the second power =0
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I dont get the question so im going to show you both solutions
if you’re asking for (2m+5)²=0 then
(2m+5)²=0 /√
2m+5=0
m=-5/2

if you’re asking only for (2m+5)² then
4m²+20m+25
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3 years ago
How is the product of 3 and 2 shown on a number line?
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Step-by-step explanation:

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What is the sum of all values of m that satisfy 2m (squared) -16m+8=0?
vodomira [7]
<h2>Steps:</h2>

So for this, we will be completing the square to solve for m. Firstly, subtract 8 on both sides:

2m^2-16m=-8

Next, divide both sides by 2:

m^2-8m=-4

Next, we want to make the left side of the equation a perfect square. To find the constant of this perfect square, divide the m coefficient by 2, then square the quotient. In this case:

-8 ÷ 2 = -4, (-4)² = 16

Add 16 to both sides of the equation:

m^2-8m+16=12

Next, factor the left side:

(m-4)^2=12

Next, square root both sides of the equation:

m-4=\pm \sqrt{12}

Next, add 4 to both sides of the equation:

m=4\pm \sqrt{12}

Now, while this is your answer, you can further simplify the radical using the product rule of radicals:

  • Product rule of radicals: √ab = √a × √b

√12 = √4 × √3 = 2√3.

m=4\pm 2\sqrt{3}

<h2>Answer:</h2>

In exact form, your answer is m=4\pm \sqrt{12}\ \textsf{OR}\ m=4\pm 2\sqrt{3}

In approximate form, your answers are (rounded to the hundreths) m=7.46, 0.54

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3 years ago
For non zero X and Y if X + Y = 0 then​
S_A_V [24]
Either X or Y is negative. One has to be
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