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Yuki888 [10]
3 years ago
13

Helppppppppppppppppppppppp

Mathematics
2 answers:
ss7ja [257]3 years ago
3 0
The answer is 1 11/15! Hope this helps!
Novosadov [1.4K]3 years ago
3 0

1 1/15 is the anwser

first we put in improper fraction 3 2/5 its 17/5 for 1 2/3 is 5/3

first find the common denominator which is 15 so like this:

3 6 9 12 15

5 10 15

the common denominator is 15 now we have to multiply the numerator by how many time we did to the bottom so now are new number are

51/15 -20/15

=31 15

now make it to a proper fraction and 1 1/15 is the anwser

have a good day have any question just ask in the comments also look at this is would help also if you have question please ask away

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7 0
3 years ago
Read 2 more answers
Which equation represents a line that passes through (5, 1) and has a slope of ?
lys-0071 [83]

Answer:

y - 1 = 5(x - 5)

Step-by-step explanation:

Given the following data;

Points (x, y) = (5, 1)

Slope = ?

From the question, the value of the slope is missing. Hence, let's assume a value of 5.

Mathematically, the equation of a straight line is given by the formula;

y = mx + c

Where;

m is the slope.

x and y are the points

c is the intercept.

To find the equation of line, we would use the following formula;

y - y1 = m(x - x1)

Substituting into the formula, we have;

y - 1 = 5(x - 5)

y - 1 = 5x - 25

y = 5x - 25 + 1

y = 5x - 24 = mx + c

5 0
3 years ago
Don’t understand, plz explain very urgent
nekit [7.7K]
Basically you have to use trigonometry to solve this. You will be using a sine ratio. Type sin-1(36/43). Use the 2nd button to do this. Your answer should be 56.84659158 but round to 57.
5 0
3 years ago
The area of this polygon is 228 square meters.
Juliette [100K]

Answer:

6

I can't tell but you can try.

3 0
3 years ago
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Based on only the information given in the diagram, which congruence postulates or theorems can be given as reasons why triangle
Lapatulllka [165]

Let's go through the choices.

A. HL, hypotenuse-leg. Yes we have a right triangle with congruent hypotenuse and leg which gives us congruent triangles, CHECK

B. HA, hypotenuse actute. Yes we have a right triangle witha congruent hypotenuse and acute angle, so congruent triangles, CHECK.

C. LL. leg leg. We don't know HL=PE so we can't use this theorem here. NO.

D. SAS, side angle side. For this one we first have to prove angle HEL is congruent to angle PME which is easily done with the Triangle Angle theorem (two congruent angles means three congruent angles) and then we can use SAS because then we have congruent sides and a congruent included angle. This one's a judgement call, I'll say NO because of the two steps.

E. AAS. Angle Angle Side, yes we have two congruent angles and a side. CHECK

F. ASA. Again we need an additional step before we conclude two angles and an included side are congruent. So again a judgement call, we'll go with NO.

7 0
3 years ago
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