8(14-9)+5
________
2
3. + 6
8(5)+5
______
9 + 6
40 + 5
————
15
45
____
15
= 3
Hi! I'm happy to help!
To solve this, we first need to look at the perimeter equation:
P=2L+2W
We don't know our length, so we can represent it with x. Since our width is 2 feet shorter than x, we can represent it with x-2. Now, we plug these values into our equation:
56=2x+(2(x-2))
Let's simplify what the width is by multiplying:
56=2x+2x-4
Now, let's combine our 2xs
56=4x-4
Now, we just need to solve for x in order to find our length and width.
First, we need to isolate x on one side of the equation. We can do this by adding 4 to both sides:
56=4x-4
+4 +4
60=4x
Now, all we have to do is divide both sides by 4 and x will be fully isolated:
60=4x
÷4 ÷4
15=x
Now that we know x, let's plug this into our previous equations:
L=x=15
<u>L=15</u>
W=x-2=15-2=13
<u>W=13</u>
To verify our answers, we can plug this into our perimeter equation:
56=2(15)+2(13)
56=30+36
56=56
After double checking our answers, we know that our length is 15 and our width is 13.
I hope this was helpful, keep learning! :D
(0,-4) would map into itself because it doesn’t move.
Answer:
C. Silver bikes
Step-by-step explanation:
Given that:
Number of red bikes at the bike shop = 11
Number of blue bikes at the bike shop = 3
Number of orange bikes at the bike shop = 4
Number of silver bikes at the bike shop = 12
Let us find the ratio of each bike with orange bikes to find the answer.
Orange bikes: Red bikes = 4 : 11
i.e. for every 4 orange bikes, there are 11 red bikes.
Orange bikes: Blue bikes = 4 : 3
i.e. for every 4 orange bikes, there are 3 blue bikes.
Orange bikes: Silver bikes = 4 : 12 = 1 : 3
<em>i.e. for every 1 orange bike, there are 3 silver bikes.</em>
<em></em>
Therefore, the answer is:
<em>C Silver bikes</em>
![\left[\begin{array}{ccc}\boxed{ \frac{L. \ Multi. \ * L. \ Num}{L.C.M}}= \frac{2*2}{10} \end{array}\right]](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cboxed%7B%20%5Cfrac%7BL.%20%5C%20Multi.%20%5C%20%2A%20L.%20%5C%20Num%7D%7BL.C.M%7D%7D%3D%20%5Cfrac%7B2%2A2%7D%7B10%7D%20%5Cend%7Barray%7D%5Cright%5D%20)
