Answer: 0.70
Step-by-step explanation:
Given : The random variable X, representing the number of accidents in a certain intersection in a week, has the following probability distribution:
x 0 1 2 3 4 5
P(X = x) 0.20 0.30 0.20 0.15 0.10 0.05
Using the above probability distribution , the the probability that in a given week there will be at most 3 accidents is given by :_

Hence, the required probability = 0.70
Answer:
$519
Step-by-step explanation:
Given the amount of profit made expressed as y=-2x^2+105x-859
At maximum profit, dy/dx = 0
dy/dx = -4x + 105
0 = -4x + 105
4x = 105
x = 105/4
x = 26.25
Substitute into the original function
y=-2x^2+105x-859
y=-2(26.25)^2+105(26.25)-859
y = - 1,378.125+2,756.25-859
y = 519.125
Hence the maximum amount of profit the company can make is $519
3*6.022*10^23 no of molecules in 3.0 moles of sucrose