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ryzh [129]
3 years ago
11

Please help me on this

Mathematics
2 answers:
Paul [167]3 years ago
8 0

Answer:

I believe all of them are correct

Step-by-step explanation:

The associative property of addition states that no matter how three values are grouped they will always equal the same thing when added. I personally would chose the first answer as that seems the most reasonable and similar to the original equation, but I'm pretty sure they're all the same because if you replace s with 1 it will always equal the same thing in each equation.

inna [77]3 years ago
6 0

Answer:

(S+8)+7

Step-by-step explanation:

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4.13 rounded to one decimal point
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The length of a rectangle is 2 feet less than twice the width. The area of the rectangle is 180 feet squared. Find the length an
Ksenya-84 [330]

Answer:

Width=10

Length=18

Step-by-step explanation:

The length is 2 feet less then twice the width

Let the width be x.

Then the length is 2x -2 based on the given information. Use this to make an equation since it is known that the area is 180feet squared.

x(2x-2)=180

2x^2 - 2x - 180 = 0

2( x^2 - x - 90) = 0

We now have a factorable quadratic.

2(x+9)(x-10)=0

So by zero product property, x=-9, x=10 Since a measure cannot be negative, -9 is an extraneous solution.

So x=10

Then the width is 10 and the length is 18

Hope this helps! Let me know if it is correct!

3 0
3 years ago
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x=1 and y=2

Step-by-step explanation:

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Can someone plz help me I’m being timed hurry!!!!!!!!
diamong [38]

Answer:

1. 14 = 2 + 12

2. 16 = 4 + 12

3. 18 = 6 + 12

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Step-by-step explanation:

Super easy. All you do is replace the numbers in your table with the corresponding letter. In this case we have a table of s and f.

Example for row two: f = s + 12. Replace s with 4 ( 4 is from your s column so you would replace it with that) then solve and plug in your answer (When you solve your answer, it will go under f column).16 = 4 + 12 . f = 16, s = 4.

Formula = f = s + 12.

1. 14 = 2 + 12

2. 16 = 4 + 12

3. 18 = 6 + 12

4. 20 = 8 + 12

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3 years ago
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